Question

我有一个表单，提交提供给数据库的数据。我有以下代码：

 <?php


$valid=true;
 function is_empty($field,$msg){
    if($field==""){
        echo $msg;  
    }
 }
if(isset($_POST['register'])){  
//PHP FIELD VALIDATIONS



if(is_empty($_POST['fname'],"First name is required <br/>")){
        $valid=false;
    }
else{
    $fname=$_POST['fname'];
}

if(is_empty($_POST['lname'],"Last name is required <br/>")){
        $valid=false;
    }
else{
    $lname=$_POST['lname'];
}
if(is_empty($_POST['email'],"Email is required <br/>")){
        $valid=false;
    }
else{
    $email=$_POST['email'];
}
if(is_empty($_POST['pword'],"Password is required <br/>")){
        $valid=false;
    }
else{
    $pword=$_POST['pword'];
}


if($valid==true)

{



require_once 'scripts/connect_to_mysql.php';
//====USING PREPARED STATEMENTS TO PREVENT SQL INJECTION
$sql = "INSERT INTO customer ".
       "(First_name,Last_name,Email, Password, date_added) ".
       "VALUES(?,?,?,?,?)";
$stmt=$conn->prepare($sql);//preparing the statement
if(!$stmt){
    echo "Unable to prepare: ".$conn->errno. " " .$conn->error;
}
//executing the statement
$date=date('d m Y h:i:s');
if(!$stmt->bind_param('sssss', $fname, $lname, $email, $pword, $date)){
    echo "Binding parameters failed: ".$stmt->errno. " " . $stmt->error;//bind parameters to sql statement. 
}
if(!$stmt->execute()){//executing the statement
    echo "Statement Execution failed: ". $stmt->error;
}

if($stmt->affected_rows==1){
    echo $stmt->affected_rows;
echo "<span style='color:green;'>Entered data successfully</span>";
}
else{
    echo "Your data was not saved! Please check your inputs";
}
    }
$stmt->close();//closing the perpared statement
$conn->close();//closing the connection   

}
?>

它将affected_rows作为1回显，但是当我在数据库中检查我的表时，没有添加新记录。请问我做得对不对？

数据未显示在数据库中

0 个答案: