Question

我有以下SQL语句：

SELECT Distinct(Venue_Name), Count(*) as `num1` 
FROM venuetagview 
INNER JOIN 
(
SELECT Tag,COUNT(*) AS `num` 
FROM usertags 
WHERE UserID=4
GROUP BY Tag 
ORDER BY `num` DESC
) as a 
ON venuetagview.Tag=a.Tag 
GROUP BY Venue_Name 
ORDER BY `num1` DESC

我正在尝试使用venuetagview表中的纬度/经度为其添加“距离”计算。我试过这个：

SELECT  
  ( 6371 
  * acos( cos( radians(51.529099) ) 
  * cos( radians( Venue_Latitude ) ) 
  * cos( radians( Venue_Longitude ) 
  - radians(-0.084981) ) 
  + sin( radians(51.529099) ) 
  * sin( radians( Venue_Latitude ) ) ) ) AS distance, 
Distinct(Venue_Name), 
Count(*) as `num1` 
FROM venuetagview 
INNER JOIN 
(
SELECT Tag,
COUNT(*) AS `num` 
FROM usertags 
WHERE UserID=4
GROUP BY Tag 
ORDER BY `num` DESC
) as a 
ON venuetagview.Tag=a.Tag 
GROUP BY Venue_Name 
ORDER BY `num1` DESC

但是我在使用它时遇到错误。

Answer 1

我发布的查询仅显示

distinct是关键作品，应该像distinct column_name
一样使用
SELECT Distinct (Venue_Name)应该是SELECT Venue_Name或 SELECT Distinct Venue_Name

Answer 2

如草莓所述，DISTINCT解决了这个问题：

SELECT ( 6371 * acos( cos( radians(51.529099) ) * cos( radians( Venue_Latitude ) ) * cos( radians( Venue_Longitude ) - radians(-0.084981) ) + sin( radians(51.529099) ) * sin( radians( Venue_Latitude ) ) ) ) AS distance, Venue_Name, Count(*) as {NUM1 {1}} {NUM {1}} {NUM {1}}

计算组合表的距离

2 个答案: