无法使用javascript从html页面中的url检索JSON数据

时间:2014-04-10 10:02:26

标签: javascript jquery html json

我已经创建了一个示例WCF服务,用于从数据库中检索数据并在浏览器中将其显示为JSON数据。此任务已成功完成。

网址收到的JSON数据是:

{"shipmentDetails":[{"Name":"AAA","Number":"123"},{"Name":"BBB","Number":"321"}]}

创建上述服务后,我的任务是在单击按钮时在html页面中查看相同的数据。我使用javascript / jQuery从URL接收数据,但是当我点击按钮时没有执行任何操作。

以下是带有javascript的HTML:

<html>
<head>
<title>JSON</title>
<script language="javascript" type="text/javascript" src="http://code.jquery.com /jquery-1.5.min.js">
</script>

 <script language="javascript" type="text/javascript" >
 $(document).ready(function(){
     $("testButton").click(function() {
        $.ajax({
           type: "GET",
           dataType: 'jsonp',
           contentType: "application/jsonp; charset=utf-8",
           url: "http://localhost:4148/EIS.svc/getShipment/arun/arun",
           success: function (data) {
               obj = eval('(' + data + ')');
               alert(obj);
               var innerHtml = "";
               document.getElementById('test').innerHTML=obj;
                      //'test' is ID of <label1>
               document.getElementById('testlab').innerHTML=obj.shipmentDetails[0].Name;
                     //'testlab' is ID of <label2>
               $("#test").html(innerHtml);
               alert("JSON DATA");
               alert(obj.shipmentDetails[0].Number);
               },
               error: function (XMLHttpRequest, textStatus, errorThrown) {

                alert("Error while retrieval – " + XMLHttpRequest.responseText+":"+textStatus+":"+errorThrown);

                }

             });
         });
      });


</head>
<body>
<input type="button" id="testButton" value="GET JSON"/>
<label id="test"></label>
<label id="testlab"></label>
</body>
</html>

2 个答案:

答案 0 :(得分:2)

看一下你的网址是一个字符串而不是变量名!

 type: 'GET',
url: serviceURL /* instead of 'serviceURL'*/,

这是完整的代码

  $('#testButton').click(function() {
          //'testButton' is ID of button input type in html
    alert("Button clicked");
        var serviceURL="http://localhost:4148/EIS.svc/getShipment/json/data";
     $.ajax({
         type: 'GET',
     url: serviceURL,
     data:$('#serviceURL').serialize(),
     processData: false,
     dataType: 'jsonp',
     contentType: "application/jsonp; charset=utf-8",
     //If the call succeeds
     success:function (data) {
         alert(data);
     },

     //If the call fails

     error: function (XMLHttpRequest, textStatus, errorThrown) {

     alert("Error while retrieval – " +         XMLHttpRequest.responseText+":"+textStatus+":"+errorThrown);

     }

     });
        return false;
     });

答案 1 :(得分:0)

对于使用从URL返回的JSON数据,必须将其包装在回调函数中,如下所示:

包装数据之前的URL是:

[http://localhost:4148/EIS.svc/getShipment/json/data]

在回调函数中包装数据后的URL是:

[http://localhost:4148/EIS.svc/getShipment/json/data?callback=jsonpexp]

在URL中进行上述更改后,浏览器中返回的数据如下所示:

jsonpexp({"shipmentDetails":[{"Name":"AAA","Number":"123"},{"Name":"BBB","Number":"321"}]});

然后它需要在javascript中进行更改,如下所示:

  $('#testButton').click(function() {
          //'testButton' is ID of button input type in html
       $.ajax({
       type: "GET",
       dataType: 'jsonp',
       contentType: "application/jsonp; charset=utf-8",
       url: "http://localhost:4148/EIS.svc/getShipment/arun/arun?callback=jsonpexp",
       jsonpCallback: 'jsonpexp',
       success: function (data) {

           var innerHtml = "";
           document.getElementById('test').innerHTML=data.shipmentDetails[0].Name;;
                  //'test' is ID of <label1>
           document.getElementById('testlab').innerHTML=data.shipmentDetails[0].Number;
                 //'testlab' is ID of <label2>
           document.getElementById('test2').innerHTML=data.shipmentDetails[1].Name;;
           //'test2' is ID of <label3>
             document.getElementById('testlab2').innerHTML=data.shipmentDetails[1].Number;
          //'testlab2' is ID of <label4>           
           },
           error: function (XMLHttpRequest, textStatus, errorThrown) {

            alert("Error while retrieval – " + XMLHttpRequest.responseText+":"+textStatus+":"+errorThrown);

            }

         });
        return false;
     });