我想以递归方式提取电子邮件表单网站,以便如果某个网站有其他电子邮件链接,它也会遍历这些网页并提取email-id:s。
我为深度级别2执行了以下操作:
wget -r -l 2 -O - some site name |grep -E -o "[a-z0-9.]+@[a-z0-9.-]+.[a-z]{2,4}">>some.txt
但是当我执行此命令时,它只会创建一个文件" some.txt
"并且不会提取任何email-id:s。
答案 0 :(得分:1)
为什么不在本地执行递归wget并存储该站点,然后在本地文件系统上的站点上执行递归grep(grep -r)?只需在脚本末尾添加一个rm -Rf即可在完成后删除该站点。
答案 1 :(得分:0)
根据使用PHP: 第1点)。开发人员以HTML实体格式添加电子邮件ID(rish)HTML实体:
第2点)。电子邮件写在href =“mailto:your@example.com”上。因此,我们可以将此作为常规表达。
<?php
$str = '<div class="call-to-action ">
<a title="Email" class="contact contact-main contact-email "
href="mailto:info@canberraeyelaser.com.au?subject=Enquiry%2C%20sent%20from%20yellowpages.com.au&
body=%0A%0A%0A%0A%0A------------------------------------------%0AEnquiry%20via%20yellowpages.com.au%0Ahttp%3A%2F%2Fyellowpages.com.au%2Fact%2Fphillip%2Fcanberra-eye-laser-15333167-listing.html%3Fcontext%3DbusinessTypeSearch"
rel="nofollow" data-email="info@canberraeyelaser.com.au">
<span class="glyph icon-email border border-dark-blue with-text"></span><span class="contact-text">Email</span>
<a href="mailto:rishabhdubey20@gmail.com">
</a>
</div>';
// $str = file_get_contents(http://example.com) ; (to get emails from URL in place of file_get_contents i use to prefer CURL) .
$str = html_entity_decode($str);
$regex = "/mailto:([^?]*)/";
if ($rex = preg_match_all($regex, $str,$matches_out)) {
echo "Found a match!";
echo "<pre>";
var_dump($matches_out[0]);
} else {
echo "The regex pattern does not match. :(";
}
?>