Question

我正在创建一个获取串行输入的程序，将其转换为int然后将引脚设置为HIGH，无论输入多久，例如，如果我将“9000”打印到Arduino串口，它将设置引脚13至HIGH为9000毫秒。但是，它将引脚设置为HIGH，以便在连接开始时进行初始“握手”。有没有办法消除这个，或者反击它？

这是我目前的Arduino代码：

int Relay = 13;
//The pin that the relay is attached to
int time;
//Creates temp variable

void setup() {
    //Initialize the Relay pin as an output:
    pinMode(Relay, OUTPUT);
    //Initialize the serial communication:
    Serial.begin(9600);
}

void loop() {
    while(true) {
        //Check if data has been sent from the computer:
        if (Serial.available()) {
                    //Assign serial value to temp
            time = Serial.parseInt();
            //Output value to relay

                    delay(4000);
                digitalWrite(Relay, HIGH);
                delay(time);
            digitalWrite(Relay, LOW);
        }
    }
}

如果有任何办法可以让我知道我该怎么办？

谢谢：）

编辑1：

int Relay = 13;
//The pin that the relay is attached to
int time;
byte byte_1;
byte byte_2;
//Creates temp variable

void setup() {
  pinMode(Relay, OUTPUT);
  //Initialize the serial communication:
  Serial.begin(9600);
  digitalWrite(Relay, LOW);
  delay(250);
}

void loop() {
  //Check if data has been sent from the computer:
  if (Serial.available() == 2) {
      byte_1 = Serial.read();
      delay(100);
      byte_2 = Serial.read();
  }                   

  if(byte_1 == 16) {
      digitalWrite(Relay, HIGH);
      delay(byte_2);
      digitalWrite(Relay, LOW); 
  }

  byte_1 = 0;
  byte_2 = 0;
}

编辑3：

package net.arduino;

import java.io.OutputStream;

import gnu.io.CommPort;
import gnu.io.CommPortIdentifier;
import gnu.io.SerialPort;

public class Main {
    public static void main(String[] args) throws Exception {
        CommPortIdentifier portIdentifier = CommPortIdentifier.getPortIdentifier("COM3");

        if(portIdentifier.isCurrentlyOwned()) {
            System.out.println("ERROR!!! -- Port already in use!");
        }else{
            CommPort commPort = portIdentifier.open("XBell", 0);

            if(commPort instanceof SerialPort) {
                SerialPort serialPort = (SerialPort) commPort;
                serialPort.setSerialPortParams(9600, SerialPort.DATABITS_8, SerialPort.STOPBITS_1, SerialPort.PARITY_NONE);

                OutputStream out = serialPort.getOutputStream();
                byte[] buffer = new byte[2];
                buffer[0] = (byte) 16;
                buffer[1] = (byte) 1000;

                out.write(buffer);
                out.flush();
                Thread.sleep(10000);
                out.close();
            }else{
                System.out.println("ERROR!!! -- This is not normal");
            }
        }
    }
}

Answer 1

您也没有检查输入的有效性（time = Serial.parseInt（）），因此线上的任何噪声都将作为有效输入值。我使用命令协议将我的调用包装到Arduino，这样我就可以确定Arduino获得了发送的值而不是噪声。即首先发送16为GetReadyToReceive，然后是值。这样就可以减少误输入的可能性。

在http://playground.arduino.cc/Csharp/SerialCommsCSharp上查看我的代码

消除Arduino Serial上的线路噪音

1 个答案: