Question

我正在尝试使用JMockit测试静态方法。此方法使用实用程序类静态方法。

当测试运行时，JMockit会抱怨并抛出以下异常：


    Test set: com.company.pkg.subpkg.mylib.test.ServiceCommunicationTest
    --------------------------------------------------------------------
    Tests run: 1, Failures: 0, Errors: 1, Skipped: 0, Time elapsed: 0.086 sec  FAILURE!
    testMakeResourceRequestPositive(com.company.pkg.subpkg.mylib.test.ServiceCommunicationTest)  Time elapsed: 0.085 sec   ERROR!
    mockit.internal.UnexpectedInvocation: Parameter "requestToSend" of com.company.pkg.subpkg.mylib.NetworkUtil#sendHttpRequest(org.apache.http.client.methods.HttpUriRequest requestToSend) expected GET https://localhost HTTP/1.1, got GET https://localhost HTTP/1.1
        at com.company.pkg.subpkg.mylib.NetworkUtil.sendHttpRequest(NetworkUtil.java)
        at com.company.pkg.subpkg.mylib.serviceaccess.client.ServiceCommunicator.makeResourceRequest(ServiceCommunicator.java:57)
        at com.company.pkg.subpkg.mylib.test.ServiceCommunicationTest.testMakeResourceRequestPositive(ServiceCommunicationTest.java:79)
        at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
        at java.lang.reflect.Method.invoke(Method.java:606)
        .    .    .
        .    .    .

以下是导致抛出异常的测试 -



    @RunWith(JUnit4.class)
    public class ServiceCommunicationTest {

        @Mocked
        private NetworkUtil _mockedNetworkUtil;

        @Test
        public void testMakeResourceRequestPositive() throws IOException {

            ResourcesDTO resDto = null;
            final String jsonResponse = JsonResponsesTestUtil.SUCCESSFUL_RESOURCES_RESPONSE;

            final String serviceUrl = "https://localhost";
            final HttpUriRequest requestToSend = new HttpGet(serviceUrl);

            new Expectations() {
                {
                    NetworkUtil.validateStringInput(serviceUrl, "rootUri");

                    NetworkUtil.sendHttpRequest(requestToSend);
                    returns(jsonResponse);
                }
            };

            // Make the actual call …
            try {
                resDto = ServiceCommunicator.makeResourceRequest(serviceUrl);
            } catch (IOException e) {
                Assert.fail("Failed to parse/obtain the Resources DTO: " + e.getMessage());
            }

            Assert.assertNotNull(resDto);
            Assert.assertNotNull(resDto.getSelfUri());
        }
    }

令人困惑的一点是，预期字符串和实际字符串（如异常中所报告的那样） -

expected GET https://localhost HTTP/1.1
     got GET https://localhost HTTP/1.1

测试方法在这里 -

public static ResourcesDTO makeResourceRequest(String rootUri) throws IOException {

    NetworkUtil.validateStringInput(rootUri, "rootUri");

    // Preparing HTTP Request ...
    HttpUriRequest requestToSend = new HttpGet(rootUri);

    // Headers that needs to be set ...
    requestToSend.addHeader(HttpHeaders.ACCEPT,       MimeConstants.CONTENT_TYPE_STRING);

    // Send Request to Authorization Service ...
    String response = NetworkUtil.sendHttpRequest(requestToSend);

    // Got the response, construct a DTOs out of it ...
    StringReader reader = new StringReader(response);

    // Convert the JSON response to appropriate DTO ...
    ObjectMapper mapper = new ObjectMapper();
    ResourcesDTO resourcesDto = mapper.readValue(reader, ResourcesDTO.class);

    return resourcesDto;
}

上述方法引用的实用程序类是 -



    public final class NetworkUtil {

        // Prevent Instance Creation …
        private NetworkUtil() {
        }

        public  static  ResourcesDTO  makeResourceRequest(String  rootUri)  throws  IOException {

            NetworkUtil.validateStringInput(rootUri, "rootUri");

            // Preparing HTTP Request ...
            HttpUriRequest requestToSend = new HttpGet(rootUri);

            // Headers that needs to be set ...
            requestToSend.addHeader(HttpHeaders.ACCEPT,   MimeConstants.CONTENT_TYPE_STRING);

            // Send Request to the Server ...
            String response = NetworkUtil.sendHttpRequest(requestToSend);

            // Got the response, construct a DTOs out of it ...
            StringReader reader = new StringReader(response);

            // Convert the JSON response to appropriate DTO ...
            ObjectMapper mapper = new ObjectMapper();
            ResourcesDTO resourcesDto = mapper.readValue(reader, ResourcesDTO.class);

            return resourcesDto;
        }
    }

谁能看到这里发生了什么？

Answer 1

最后，我能够确定这种意外调用异常的原因。

NetworkUtil.sendHttpRequest((HttpUriRequest) any);
returns(jsonResponse);

如上所示，我在Expectations块中更改了返回之前的行。现在我告诉JMockit 任何类型为HttpUriRequest的对象都是可接受的，而不是传递HttpUriRequest类型的对象。

我相信，JMockit对模拟API调用的参数执行equals（）。这里的问题可能是HttpUriRequest deosn实现了自己的equals（）方法，而不是从Object继承。这意味着它实际上是在做一个object1 == object2。

模拟静态方法调用时的UnexpectedInvocation

1 个答案: