Question

在我的应用程序中，我有3个型号：

OrganizationType
组织
OrganizationTypeLink 如你所知：我的组织可以执行多项操作，而这种类型的操作我想与组织联系......

在控制器中我这么写：

def create
    @admin_organization = Organization.new(admin_organization_params)
@admin_organization.organization_type_links.build(organization_type_id: params[:organization_type_id], organization_id: @admin_organization.id)
if @admin_organization.save
....

在模型OrganizationTypeLink中，我在db中看到了新行，但是如何在Organization organization_type_link_id中存储？我怎么能把它存储在数据库中？

我是RoR的新手，所以请提供建议）

UPD：

class Organization < ActiveRecord::Base
  belongs_to :organization_type
  has_many :organization_type_links, :dependent => :destroy
end

class OrganizationTypeLink < ActiveRecord::Base
  belongs_to :organization
  belongs_to :organization_type
end

class OrganizationType < ActiveRecord::Base
  has_many :organizations
  has_many :organization_type_links
end

Answer 1

如何在Organization_type_link_id中存储？我怎么能把它存放在db？

您目前在这3个模型中定义关联的方式：OrganizationType, Organization and OrganizationTypeLink

Organization has_many organization_type_links表示OrganizationTypeLink将在其中包含名为organization_id的外键，而不是相反。

如果您想在组织中拥有organization_type_link_id，则需要将关联设置为：

class Organization < ActiveRecord::Base
  belongs_to :organization_type
  belong_to :organization_type_link
end

class OrganizationTypeLink < ActiveRecord::Base
  has_many :organizations, :dependent => :destroy
  belongs_to :organization_type
end

Rails模型.build设置id

1 个答案: