Question

我似乎无法想出这一个，我确信它很简单。每当我按下“更新/保存”按钮，我的代码就会进入我的Order类来执行{get; set}。但是，它将我的PhonePrimary字段传递为“null”，这会导致错误。

以下是EditOrder.cshtml页面

       @using (Html.BeginForm())
         {
           <div class="form-group-PhonePrimary">
                <div class="input-group" style="border-right:0px">
                    <span class="input-group-addon" style="text-align: left; border-right: 0px; min-width: 115px">Phone #</span>
                        @Html.TextBoxFor(model => model.order.PhonePrimary, new { @class = "form-control", @maxlength = "13" })
                        @Html.ValidationMessageFor(model => model.order.PhonePrimary)
                </div>
            </div>

        <div class="form-group" style="padding-left:5px">
            <div class="btnUpdateSave">
                <input type="submit" value="Update/Save" class="btn btn-primary col-md-10" />
            </div>
        </div>
       }

以下是Order类。

public class Order
{
        private string _PhonePrimary;
                [DisplayName("Phone Primary")]
        public string PhonePrimary
        {
            get
            {
                //this._PhonePrimary = BeautifyPhoneNumber(this._PhonePrimary);

                return BeautifyPhoneNumber(this._PhonePrimary);
            }
            set
            {
                this._PhonePrimary = value;
            }
        }
    }

以下是EditOrder.cshtml页面中使用的EditOrderViewModel

public class EditOrderViewModel
{
    public Order order { get; set; }
    public List<Status> StatusOptions { get; set; }
    public IEnumerable<Document> Documents { get; set; }
    public IEnumerable<Notary> Notaries { get; set; }
    public Notary NotaryAssigned { get; set; }
}

下面是SchedulingController.cs中的httpget和httppost

        [HttpGet]
        public ActionResult EditOrder(int id)
        {
            var model = repositoryScheduling.Order_FindById(id);//returns EditOrderViewModel

            model.NotaryAssigned = repositoryScheduling.Notary_FindAssignedNotary(model.order.Id);

            return View(model);
        }
     [HttpPost]
        public ActionResult EditOrder(EditOrderViewModel orderModel)
        {
            try
            {
                repositoryScheduling.Order_Update(orderModel);
                return RedirectToAction("OrderIndex");
            }
            catch (MySql.Data.MySqlClient.MySqlException ex)
            {
                return View();
            }
        }

这是SchedulingREpository.cs中的Order_FindById函数。我正在使用Dapper来帮助处理SQL命令。

    public EditOrderViewModel Order_FindById(int id)
    {
        var parameters = new DynamicParameters();

        parameters.Add("@ID", value: id);

        var query = @"long query string that i dont want to put";

        using (var multi = this.db.QueryMultiple(query, parameters))
        {
            EditOrderViewModel editVM = new EditOrderViewModel();
            editVM.order = multi.Read<Order>().SingleOrDefault();
            editVM.StatusOptions = multi.Read<Status>().ToList();
            editVM.Documents = multi.Read<Document>().ToList();
            return editVM;
        }
    }

每当我切换到使用model.order._PhonePrimary而不是当前代码中的model.order.PhonePrimary时（BeautifyNumber()）。我没有收到任何错误，但我的{{1}}永远不会被触发。

Answer 1

确保在将模型分配给视图之前实例化Order属性。

例如：

public ActionResult EditOrder() {
    var vm = new EditOrderViewModel();
    vm.Order = new Order();
    return View(vm);
}

编辑：在你的回购中试试这个：

editVM.order = multi.Read<Order>().SingleOrDefault() ?? new Order();

编辑2：这可能是一个模型绑定问题。您可以考虑使用自定义模型绑定器进行POST操作，或者您可以通过直接在视图模型中引用PhonePrimary来绕过对Order嵌套类的需要，并让您的repo在POST后将其填充并消化为Order条目。

Answer 2

所以，我不确定这是如何解决这个问题的。但它确实（现在......仍在等待更多涉及此事的错误^ _ ^）

我使用

将代码封装在BeautifyPhoneNumber()函数中

if (numberToBeautifuy != null)
{
//code
}
else
{
 return "";
}

完成的功能如下。

    public static String BeautifyPhoneNumber(string numberToBeautify)
    {
        if (numberToBeautify != null)
        {


            //The below gives us capture groups for each 
            //individual piece of the number.
            var regularExpression = new Regex(@"(\d{3})(\d{3})(\d{4})(x\d*)?");
            //This matches a number that's already been beautified, 
            //so we can guard against beautifying twice.
            var alreadyBeautifulExpression = new Regex(@"(\(\d{3}\)) (\d{3})-(\d{4}) ?(x\d*)?");
            var beautifulNumber = string.Empty;
            var separator = "-";
            var space = " ";
            //This prevents us from accidentally beautifying 
            //something more than once
            //You could also guard against this in your getter using a
            //IsBeautified extension, using the alreadyBeautifulExpression above
            if (alreadyBeautifulExpression.IsMatch(numberToBeautify))
            {
                return numberToBeautify;
            }

            //Trying to protect against invalid input... May be insufficient,
            //Or unnecessary
            if (string.IsNullOrEmpty(numberToBeautify)
                || regularExpression.Matches(numberToBeautify).Count <= 0)
            {
                return beautifulNumber;
            }

            GroupCollection groups = regularExpression.Matches(
                numberToBeautify)[0].Groups;

            //More protection against invalid input
            if (groups.Count <= 3)
            {
                return beautifulNumber;
            }

            //Given "7689131234",
            beautifulNumber += "(" + groups[1] + ")" + space; //gives us "(768) "
            beautifulNumber += groups[2] + separator; //gives us "(768) 913-"
            beautifulNumber += groups[3]; //gives us "(768) 913-1234"
            //If we have an extension, we add it.
            if (groups[4] != null)
            {
                beautifulNumber += space + groups[4];
            }

            return beautifulNumber;
        }
        else
        {
            return "";
        }
    }

如果有人可以向我解释为什么会有效，那就太棒了，我会给你答案＆＃39;分。

POST请求并获取设置动作MVC

2 个答案: