Question

我已经不知疲倦地试图做到这一点，但似乎没有任何效果。我做的很多事情都让我误以为“控制可能会达到无效功能的终结”。

基本上，我们创建了一个输出燃气使用统计数据的程序。我坚持的是： “在4年的时间内，天然气的价格将从定义的初始值上升到规定的最终值，然后在接下来的4年内保持固定在更高的值。”

我觉得应该有一个循环或函数，但每次我将NUM_YEARS设为int而不是const，无论程序告诉我'控件可能达到非空函数的结束。'

以下是该计划：

#include <cstdlib>
#include <iostream>

using namespace std;

const int MILES_PER_YEAR = 21000;
const double CITY_PERCENT = 45.0;
const double HIGHWAY_PERCENT = 55.0;
const double CITY_MPG = 51.0;
const double HIGHWAY_MPG = 45.0;
const double USABLE_GAS = 9.0;
const double INITIAL_PRICE = 3.359;
const double FINAL_PRICE = 6.00;
const int NUM_YEARS = 8; //This will be the total number of years

double gasPrice(int day);

int main(int argc, char * argv[]) {
   cout << "Driving the Toyota Prius" << endl;
   double daily_miles = MILES_PER_YEAR / 365.0;
   double daily_city_miles = daily_miles * CITY_PERCENT/100.0;
   double daily_highway_miles = daily_miles*HIGHWAY_PERCENT/100.0;
   double daily_gas_consumed = daily_highway_miles / HIGHWAY_MPG +
   daily_city_miles / CITY_MPG;
   double gas_in_tank = USABLE_GAS;
   double price;
   double amount_purchased;
   double gallons_purchased;
   double total_gas_purchases = 0;

   for(int day = 0;day < 365*8; day++) { //If the day is less than the total number of days                 in 8 years, add one day
      cout << "Driving summary for day " << day << endl;
      cout << " highway miles: " << daily_highway_miles << endl;
      cout << " city miles   : " << daily_city_miles << endl;
      cout << " gas consumed : " << daily_gas_consumed << endl;
      gas_in_tank = gas_in_tank - daily_gas_consumed;
      cout << " gas in tank  : " << gas_in_tank << endl;

      if (gas_in_tank < 0.0) {
        cout << "  BUY GAS" << endl;
        gallons_purchased = USABLE_GAS - gas_in_tank;
        price = gasPrice(day);
        cout << "  price today is   : " << price << endl;
        cout << "  Gallons purchased: " << gallons_purchased << endl;
        cout << "  fillup cost      : " << gallons_purchased * price << endl;
        total_gas_purchases = total_gas_purchases + gallons_purchased * price;
        cout << "  total gas cost   : " << total_gas_purchases << endl;
        gas_in_tank = USABLE_GAS;
      }
   }

   system("PAUSE");
   return EXIT_SUCCESS;
}

double gasPrice(int day, int YEAR_NUM) {
if (int day=365) { //call YEAR_NUM, for day=365, increase YEAR_NUM by 1
    YEAR_NUM++;
    day = 0;
}
if (YEAR_NUM >= 4) {
    double currentPrice = FINAL_PRICE;
    currentPrice;

}
if (YEAR_NUM < 4) { //conditional price for the first four years
    double dailyIncrease = (FINAL_PRICE - INITIAL_PRICE) / (NUM_YEARS * 365);
    double currentPrice = (INITIAL_PRICE + day * dailyIncrease);
    return currentPrice;
}
}

Answer 1

您需要在gasPrice循环之外的for中返回一些内容。编译器说有可能不会满足while条件，在这种情况下没有值可以返回。

另一方面，while循环对它们的编写方式没有多大意义。只需要他们if语句。

Answer 2

我认为如果你移动＆＃34;返回currentPrice;＆＃34;在这两个while循环中，它将解决问题。

Answer 3

函数gasPrice在for循环之外没有return语句。由于函数的返回类型不是void，因此如果不存在return语句，则函数的行为将是未定义的。

介绍性的C ++程序

3 个答案: