Question

我的文件名为Sample File_20140408201420(20140409_0).xlsx

我在我的C＃代码中将模式设置为'Sample File'+ @"(.*)\.xlsx"，但正则表达式匹配不起作用。 20140408201420（20140409_0）是基于文件名更改的部分。

我应该使用的正确的正则表达式模式是什么？

Answer 1

试试这个正则表达式：

static Regex rxFileNamePattern = new Regex( @"
  ^           # anchor the match at start-of-text, followed by
  Sample File # the literal "Sample File", followed by
  \d+         # 1 or more decimal digits, followed by
  \(          # a literal left/open parenthesis "(", followed by
  \d+         # 1 or more decimal digits, followed by
  _           # a literal underscore "_", followed by
  \d+         # 1 or more decimal digits, followed by
  \)          # a literal right/close parenthesis ")", followed by
  \.xlsx      # the literal ".xlsx", followed by
  $           # end-of-text
  " , RegexOptions.IgnorePatternWhitespace ) ;

Answer 2

using System;
using System.Text.RegularExpressions;

class Program
{
    static void Main()
    {
    // First we see the input string.
    string input = "Sample File_20140408201420(20140409_0).xlsx";

    // Here we call Regex.Match.
    Match match = Regex.Match(input, @"Sample File_(.*)\.xlsx",
        RegexOptions.IgnoreCase);

    // Here we check the Match instance.
    if (match.Success)
    {
        // Finally, we get the Group value and display it.
        string key = match.Groups[1].Value;
        Console.WriteLine(key);
    }
    }
}

我做了什么？

我已将正则表达式更改为：

@"Sample File_(.*)\.xlsx"

这将返回值：

20140408201420(20140409_0)

我想这就是你要找的东西

Answer 3

您可以试试Regex：

var matches = Directory.GetFiles(@"c:\temp").Where(path => Regex.Match(path, @"Sample File_[0-9]{14}(.*)\.xlsx").Success);

如果您不在乎数量，可以试试这个：

var matches = Directory.GetFiles(@"c:\temp").Where(path => Regex.Match(path, @"Sample File_(.*)\.xlsx").Success);

文件模式的正则表达式

3 个答案: