Question

我在Parse上有一个云功能。当它被调用时，它会检索PFObject，然后在该对象和用户之间添加关系。这部分工作正常（见功能结束）。我无法获取选择PFObject的查询以忽略用户已与之相关的查询

这是我的代码：

Parse.Cloud.define("NextMedia", function (request, response) {

    var LikeRequest = Parse.Object.extend("LikeRequest");
    var query = new Parse.Query(LikeRequest);

    query.equalTo("completed", false);
    console.log("user: " + Parse.User.current().id);

    query.notEqualTo("user", Parse.User.current());

    // Also only fetch if never been sent before 
    // HERE SHOULD USE THE BELOW RELATIONSHIP
    var innerQuery = new Parse.Query(Parse.User);
    innerQuery.exists(Parse.User);
    query.matchesQuery("sentTo", innerQuery);

    query.ascending("createdAt");

    query.first({

        success: function (object) {
            // Successfully retrieved the object.
            console.log("Got 1 object: " + object.get('mediaId'));

            // Record that the user has been sent it
            var user = Parse.User.current();
            var relation = object.relation("sentTo"); // RELATION ADDED HERE

            relation.add(user);
            object.save();

            response.success(object);
        },
        error: function (error) {
            console.log("Error: " + error.code + " " + error.message);

            response.error("Error getting next mediaId");
        }
    });
});

我确定我只是不了解关系查询语法的工作原理。

Answer 1

这段话：

// Also only fetch if never been sent before 
// HERE SHOULD USE THE BELOW RELATIONSHIP
var innerQuery = new Parse.Query(Parse.User);
innerQuery.exists(Parse.User);
query.matchesQuery("sentTo", innerQuery);

可以更改为：

// Also only fetch if never been sent before 
query.notContainedIn("sentTo",[Parse.User.current()])

有效。Parse Query

Answer 2

Query Constraints怎么办？

如果要检索与多个值不匹配的对象，可以使用notContainedIn

  // Finds objects from anyone who is neither Jonathan, Dario, nor Shawn
query.notContainedIn("playerName",
                     ["Jonathan Walsh", "Dario Wunsch", "Shawn Simon"]);

Answer 3

我认为Kerem有部分正确但不包含在你的情况下不够动态。

您需要构建query from the relation，然后使用doesNotMatchKeyInQuery从外部查询中排除这些对象。

解析云代码关系查询语法

3 个答案: