如何转置/透视SQL表

时间:2014-04-09 06:24:09

标签: sql-server sql-server-2008 pivot transpose unpivot

我有一个如下表所示的SQL表:

ID    StepID   Rating   Comments     StaffID    Date
-------------------------------------------------------------
1     1        6          blah blah     1025      2014-03-20 
1     2        6          blah blah     1025      2014-03-20 
1     3        8          blah blah     1025      2014-03-20 
1     4        7          blah blah     1025      2014-03-20 

如您所见,列ID,注释,StaffID和日期的数据重复(相同)。

如何将上表变成以下内容:

ID    Step1   Step2  Step3  Step4  Comments     StaffID    Date
----------------------------------------------------------------------------------
1      6       6      8      7    blah blah     1025    2014-03-20 

任何帮助表示赞赏!

1 个答案:

答案 0 :(得分:2)

你可以这样做:

测试数据

DECLARE @tbl TABLE(ID INT,StepID int,Rating INT, 
                   Comments VARCHAR(200), StaffID INT,Date DATETIME)

INSERT INTO @tbl
VALUES
(1,1,6,'blah blah',1025,'2014-03-20'),
(1,2,6,'blah blah',1025,'2014-03-20'),
(1,3,8,'blah blah',1025,'2014-03-20'),
(1,4,7,'blah blah',1025,'2014-03-20')

<强>查询

SELECT
    pvt.ID,
    pvt.[1] AS Step1,
    pvt.[2] AS Step2,
    pvt.[3] AS Step3,
    pvt.[4] AS Step4,
    pvt.Comments,
    pvt.StaffID,
    pvt.Date
FROM
(
    SELECT 
        * 
    FROM 
        @tbl AS tbl
) AS sourceTable
PIVOT
(
    MAX(Rating)
    FOR StepID IN ([1],[2],[3],[4])
) AS pvt

修改

如果您不知道自己有多少步骤。你需要做一个动态的支点。像这样:

测试数据

CREATE TABLE tbl
(
    ID INT,
    StepID int,
    Rating INT, 
    Comments VARCHAR(200), 
    StaffID INT,
    Date DATETIME
)

INSERT INTO tbl
VALUES
(1,1,6,'blah blah',1025,'2014-03-20'),
(1,2,6,'blah blah',1025,'2014-03-20'),
(1,3,8,'blah blah',1025,'2014-03-20'),
(1,4,7,'blah blah',1025,'2014-03-20')

获得独特的步骤:

DECLARE @cols VARCHAR(MAX)
SELECT @cols=STUFF
(
    (
        SELECT DISTINCT
            ',' +QUOTENAME('Step'+CAST(tbl.StepID AS VARCHAR(100)))
        FROM
            tbl
        FOR XML PATH('')
    )
,1,1,'')

执行动态数据透视:

DECLARE @query NVARCHAR(4000)=
'SELECT
    *
FROM
(
    SELECT 
        tbl.Comments,
        tbl.Date,
        tbl.ID,
        tbl.Rating,
        tbl.StaffID,
        ''Step''+CAST(tbl.StepID AS VARCHAR(100)) AS StepID
    FROM 
        tbl
) AS sourceTable
PIVOT
(
    MAX(Rating)
    FOR StepID IN ('+@cols+')
) AS pvt
 DROP TABLE tbl'

 EXECUTE(@query)

在我的情况下放弃桌子:

DROP TABLE tbl