Question

我使用蓝牙连接将Arduino的串行数据发送到我的Android应用程序。我用来连接Android设备的代码是BluetoothChat.java，这是用Google搜索时可以找到的示例代码。

示例代码显示ListView中的数据，我想将其存储在数组中。

以下是从Arduino读取串行打印的代码......

case MESSAGE_READ:

            byte[] readBuf = (byte[]) msg.obj;
            String readMessage = new String(readBuf);
            mConversationArrayAdapter.add(readMessage);
            int a = readBuf.length;

            //coordinates[] is the exact length necessary as given by double[a], and contains no more and
            //no fewer positions than required.

            double coordinates[] = new double[a];

            //Check the values of the data in readBuf[] and make the necessary conversions to store in the
            //variables.
            for(int i=0; i<a; i++){

                int val=readBuf[i];

                /*
                *(int) val/8 will divide val and round down to the nearest integer.
                *val%8 divides by 8 but takes the remainder which is the value of
                *all variables above x1, though the math works with x1.
                */

                coordinates[(int) val/8] = val%8;

            }

我认为我正确存储了数据。但是当我使用coordinates[]时，它并没有更改TextView我设置的文字。以下是设置文本的代码。

if(readBuf.length==4){
                double x1 = coordinates[0];
                double x2 = coordinates[1];
                double y1 = coordinates[2];
                double y2 = coordinates[3];

                r = new Regression(x1, x2, y1, y2);
                r.computation();

                leftLung.setText("Left Lung "+ r.leftLungDamage() +"% hit");
                rightLung.setText("Right Lung "+ r.rightLungDamage() +"% hit");
                heart.setText("Heart "+ r.heartDamage() +"% hit");
                liver.setText("Liver "+ r.liverDamage() +"% hit");
                smallIntestine.setText("Small Intestine "+ r.smIntestineDamage() +"% hit");
                largeIntestine.setText("Large Intestine "+ r.lgIntestineDamage() +"% hit");
                stomach.setText("Stomach "+ r.stomachDamage() +"% hit");
                spleen.setText("Spleen "+ r.spleenDamage() +"% hit");
                gallbladder.setText("Gallbladder "+ r.gallbladderDamage() +"% hit");
                lKidney.setText("Left Kidney "+ r.lKidneyDamage() +"% hit");
                rKidney.setText("Right Kidney "+ r.rKidneyDamage() +"% hit");
                pancreas.setText("Pancreas "+ r.pancreasDamage() +"% hit");
                venaCava.setText("Vena Cava "+ r.venaCavaDamage() +"% hit");
                dAorta.setText("Descending Aorta "+ r.dAortaDamage() +"% hit");
                aAorta.setText("Ascending Aorta "+ r.aAortaDamage() +"% hit");
            }

回归本身就是一个独立的Java应用程序。

Answer 1

coordinates[(int) val/8] = val%8;

这条线让我觉得奇怪的阵列对齐。您创建一个长度为readBuf的数组。那么为什么要使用(int) val/8之类的东西来存储数组中的值。

可能

coordinates[i] = val%8;

是你想要的。或者至少coordinates[i] = something是使用for循环在数组中存储值的正确方法。

从arduino中存储阵列中的串行打印数据

1 个答案: