Question

在此程序中，计算机生成一个随机数（1-100之间），用户试图猜测它。运行直到用户正确猜出数字。需要打印出正确猜出数字之前所花费的总尝试次数。程序运行正常，但存在逻辑错误。当我正确猜出数字时，没有打印出来;程序就此停止了。

import java.util.*;
public class Problem3 {


  public static void main(String[] args) { 

    Random rand = new Random();
    Scanner console = new Scanner(System.in);

    int num = rand.nextInt(100)+1;
    System.out.println(num); //prints out the random number so I know test works correctly
    int count = 0;
    System.out.println("Guess the random number. The number is between 1 and 100. Enter it below");
    console = new Scanner(System.in);
    int guess = console.nextInt();
    while(guess != num){  //while guess is not = to number  
      if(guess < num){             //if less than num
        System.out.println("Your guess is too low"); 
        System.out.println("Guess the random number. The number is between 1 and 100. Enter it below");
        guess = console.nextInt();
        count++;
      }else if( guess > num){      //if greater than num   
          System.out.println("Your guess is too high");
          System.out.println("Guess the random number. The number is between 1 and 100. Enter it below");
          guess = console.nextInt();
          count++;
      }else{
        count++;
        System.out.println("You guessed correctly after " + count + " tries!");
    }
    }
  }

}

Answer 1

实际上你永远不会进入else阶段，因为当猜到数字时，while代码不会执行，因此else代码永远不会执行。所以在那之后数字被猜到了，所以条件是false，退出while循环和System.out.print恭喜消息

将它放在你的while循环之外＆＃34;在结尾＆＃34;：

 System.out.println("You guessed correctly after " + count + " tries!");

这是您的代码应该是什么样子：

while(guess != num){  //while guess is not = to number  
      if(guess < num){             //if less than num
        System.out.println("Your guess is too low"); 
        System.out.println("Guess the random number. The number is between 1 and 100. Enter it below");
        guess = console.nextInt();
        count++;
      }else{      //if greater than num   
          System.out.println("Your guess is too high");
          System.out.println("Guess the random number. The number is between 1 and 100. Enter it below");
          guess = console.nextInt();
          count++;
      }
    }

  System.out.println("You guessed correctly after " + ++count + " tries!");

Answer 2

当猜到正确的数字时，你的while循环条件变为false。这使得其他无法访问。

修改

以下是我如何解决您的问题。如果您发现自己重复代码，通常意味着有改进的机会。不仅代码更少，而且更容易阅读和跟踪正在发生的事情。我并没有试图窃取答案（@AmirBawab首先发现了这个问题），但我非常相信不仅可以使代码有效，而且代码可以由其他人维护和阅读。希望你继续学习，你会记住这一点。快乐的编码！

public static void main(String[] args) { Random rand = new Random(); Scanner console = new Scanner(System.in); int num = rand.nextInt(100) + 1; int count = 0; while (true) { System.out.println("Guess the random number. The number is between 1 and 100. Enter it below"); int guess = console.nextInt(); count++; if (guess < num) { System.out.println("Your guess is too low"); } else if (guess > num) { System.out.println("Your guess is too high"); } else { System.out.println("You guessed correctly after " + count + " tries!"); break; } } console.close(); }

随机数猜测游戏的逻辑错误

2 个答案: