Question

我的构建中出现错误（使用cordova 3.4）：

Undefined symbols for architecture i386:
  "_iconv", referenced from:
      zxing::qrcode::DecodedBitStreamParser::append(std::string&, unsigned char const*, unsigned long, char const*) in zxing-all-in-one.o
  "_iconv_close", referenced from:
      zxing::qrcode::DecodedBitStreamParser::append(std::string&, unsigned char const*, unsigned long, char const*) in zxing-all-in-one.o
  "_iconv_open", referenced from:
      zxing::qrcode::DecodedBitStreamParser::append(std::string&, unsigned char const*, unsigned long, char const*) in zxing-all-in-one.o
ld: symbol(s) not found for architecture i386
clang: error: linker command failed with exit code 1 (use -v to see invocation)

** BUILD FAILED **

我很确定这是来自手机间隙QR扫描仪插件，但我认为它根本不应该构建i386。 qrcode扫描程序似乎没有该架构的库。

如何告诉cordova不要构建i386？或者我错过了什么？

Answer 1

构建时，您可以指定要执行的构建类型：

cordova compile --device

或i386：

cordova compile --emulator

这就是为我解决的问题。

Answer 2

我也一直在努力解决这个问题。我按照Snips中的指导回答这里，让它为我工作

libiconv not linking to iOS project

Apache Cordova - 不构建i386架构

2 个答案: