Question

提前致谢。
我想首先显示具有最多重复值的列，如下所示

col1    col2
1        A
1        B
1        C
1        D
2        A
2        B
2        C
4        D
4        E
3        A

在'col1'中，因为'1'重复四次，它应该首先重复，'2'重复三次，它是第二次。需要编写sql查询才能得到这个结果。请帮帮我。

Answer 1

假设SQL Server 2005或更新版本，您可以使用OVER()子句：

SELECT * 
FROM  Table1
ORDER BY COUNT(*) OVER (PARTITION BY col1) DESC

演示：SQL Fiddle

Answer 2

我建议你这个解决方案：

WITH temp AS (
  SELECT col1, count(col2) nb_occurences
  FROM tab
  GROUP BY
    col1)


SELECT
  tab.col1, tab.col2, nb_occurences
FROM tab
INNER JOIN
  temp
    ON temp.col1 = tab.col1
ORDER BY nb_occurences DESC

我希望这会对你有所帮助:)。

祝你好运

Answer 3

SELECT   col1
FROM     (SELECT   col1, COUNT(*) AS cnt
          FROM     my_table
          GROUP BY col1) t
ORDER BY cnt DESC

首先在sql server中显示最重复的列

3 个答案: