我的错误消息是“短语无法解析为变量”
我觉得它与新的String()有关?也许。
或者它可能是短语短语=新短语();
package edu.htc.java1.phrasegame;
import edu.htc.java1.phrasegame.model.*;
public class PhraseGameController {
public void currentPhrase() {
String p = new String();
p = Phrase;
}
}
和
package edu.htc.java1.phrasegame.model;
import java.util.ArrayList;
public class Phrase {
public void setPhrase(String phrase) {
this.phrase = phrase;
}
private String phrase;
public Phrase(String phrase) {
phrase = phrase.toUpperCase();
for(char c : phrase.toCharArray()) {
letters.add(new Letter(c));
}
}
public String getPhrase() {
return phrase;
}
ArrayList<Letter> letters = new ArrayList<Letter>();
public ArrayList<Letter> getLetters() {
return letters;
}
public boolean guessLetter(char c) {
// convert received character to letter
Letter letter = new Letter(c);
// loop through your list of letters
for(Letter l : letters) {
// if list of letters contains same letter as the one you received then return true
if(l.getLetter() == letter.getLetter()) {
letter.unhide();
// return true;
}
}
// we did not find the letter, so we return false
return false;
}
}
答案 0 :(得分:0)
我认为首先你必须导入这个包:
edu.htc.java1.phrasegame.model;
进入PhraseGameController类。通过在包声明下面添加这个,但在类声明之上:
import edu.htc.java1.phrasegame.model.*;
然后你将在该类中创建一个名为currentPhrase的新变量,如下所示:
private Phrase currentPhrase;
你从那里做的事情超出了你的问题的范围。
答案 1 :(得分:0)
实例变量是类的属性。
public class MyClass {
private static String classVariable;
private String instanceVariable;
public String instanceMethod () {
String localVariable = "hey";
}
public static String classMethod {
}
}
要实例化变量,您必须使用new
关键字:
SomeClass someInstance = new SomeClass();
或者如果你使用泛型:
List<SomeType> myList = new ArrayList<SomeType>();
所以在你的情况下它应该是:
public class PhraseGameController {
private Phrase p = new Phrase();
}