Question

首先我创建了审计表。表的代码如下：

CREATE TABLE AUDIT_NEW_1 
(   AUDIT_NUMBER NUMBER(3,0) NOT NULL, 
"CUSTOMER_NAME" VARCHAR2(20 BYTE) NOT NULl,  
"CONCERT_ID" NUMBER(5,0) NOT NULL, 
"EVENT_DATE" DATE NOT NULL,
"VENUE_ID" NUMBER(5,0), 
CONSTRAINT AUDIT_NEW_1 PRIMARY KEY (AUDIT_NUMBER)
);

bookings表的代码

   CREATE TABLE Bookings
  (
    Event_Event_ID       NUMBER (5) NOT NULL ,
    Customer_Customer_ID NUMBER (5) NOT NULL ,
    Arrival_time         TIMESTAMP ,
    Evaluation           NUMBER (1) ,
    Vehicle_Number       VARCHAR2 (7)
  ) ;

创建触发器代码：

CREATE OR REPLACE
TRIGGER LOW_EVALUAT_1
AFTER INSERT OR UPDATE OF EVALUATION ON BOOKINGS
FOR EACH ROW
DECLARE 
CUSTOMER_NAME  VARCHAR(20 CHAR);
CONCERT_ID     NUMBER (5,0);
EVENT_DATE      DATE;
VENUE_ID       NUMBER(5,0  );
BEGIN
IF (:NEW.EVALUATION = 0) THEN 
SELECT CUSTOMER.CUSTOMER_ID, CONCERT.CONCERT_ID, EVENT.EVENT_DATE, VENUE.VENUE_ID
INTO CUSTOMER_NAME,CONCERT_ID,EVENT_DATE,VENUE_ID
FROM CUSTOMER, CONCERT, EVENT, VENUE
WHERE
  CUSTOMER.CUSTOMER_ID = :NEW.CUSTOMER_ID AND
  EVENT.EVENT_ID = :NEW.EVENT_ID AND
  CONCERT.CONCERT_ID = EVENT.CONCERT_ID;

INSERT INTO AUDIT_NEW_1 VALUES (AUDIT_NUMBER.NEXTVAL, CUSTOMER_NAME, CONCERT_ID,
EVENT_DATE, VENUE_ID, :NEW.EVALUATION);             
END IF;
END;

SQL开发人员在这些行上返回错误你能帮我解决一下错误吗？：

SELECT CUSTOMER.CUSTOMER_ID, CONCERT.CONCERT_ID, EVENT.EVENT_DATE, VENUE.VENUE_ID
INTO CUSTOMER_NAME,CONCERT_ID,EVENT_DATE,VENUE_ID

错误返回

Error(12,30): PLS-00049: bad bind variable 'NEW.CUSTOMER_ID'
Error(13,24): PLS-00049: bad bind variable 'NEW.EVENT_ID'

    CREATE TABLE Bookings
  (
    Event_Event_ID       NUMBER (5) NOT NULL ,
    Customer_Customer_ID NUMBER (5) NOT NULL ,
    Arrival_time         TIMESTAMP ,
    Evaluation           NUMBER (1) ,
    Vehicle_Number       VARCHAR2 (7)
  ) ;
ALTER TABLE Bookings ADD CHECK
(
  Evaluation IN (0, 1, 2, 3, 4, 5)
)
;
ALTER TABLE Bookings ADD CONSTRAINT Relation_2__IDX PRIMARY KEY
(
  Event_Event_ID, Customer_Customer_ID
)
;

CREATE TABLE Concert
  (
    Concert_ID NUMBER (5) NOT NULL ,
    Name       VARCHAR2 (25) NOT NULL ,
    Duration   NUMBER (1) NOT NULL ,
    Type       VARCHAR2 (9) NOT NULL ,
    Cost       NUMBER (25) NOT NULL
  ) ;
ALTER TABLE Concert ADD CHECK
(
  Duration IN (2, 3, 4, 5)
)
;
ALTER TABLE Concert ADD CHECK
(
  Cost BETWEEN 30 AND 500
)
;
ALTER TABLE Concert ADD CONSTRAINT Concert_PK PRIMARY KEY
(
  Concert_ID
)
;

CREATE TABLE Customer
  (
    Customer_ID      NUMBER (5) NOT NULL ,
    Full_Name        VARCHAR2 (20) NOT NULL ,
    Gender           VARCHAR2 (6) NOT NULL ,
    Telephone_Number NUMBER (11) NOT NULL ,
    Address          VARCHAR2 (50) NOT NULL
  ) ;
ALTER TABLE Customer ADD CHECK
(
  Gender IN ('F', 'M')
)
;
ALTER TABLE Customer ADD CONSTRAINT Customer_PK PRIMARY KEY
(
  Customer_ID
)
;

CREATE TABLE Event
  (
    Event_ID   NUMBER (5) NOT NULL ,
    "Date"     DATE NOT NULL ,
    Concert_ID NUMBER (5) NOT NULL ,
    Venue_ID   NUMBER (5) NOT NULL
  ) ;
ALTER TABLE Event ADD CONSTRAINT Event_PK PRIMARY KEY
(
  Event_ID
)
;

CREATE TABLE Venue
  (
    Venue_ID NUMBER (5) NOT NULL ,
    Name     VARCHAR2 (25) NOT NULL ,
    Capacity NUMBER (6) NOT NULL ,
    PostCode VARCHAR2 (15) NOT NULL ,
    Location VARCHAR2 (20) NOT NULL
  ) ;
ALTER TABLE Venue ADD CHECK
(
  Capacity BETWEEN 1000 AND 60000
)
;
ALTER TABLE Venue ADD CONSTRAINT Venue_PK PRIMARY KEY
(
  Venue_ID
)
;

ALTER TABLE Event ADD CONSTRAINT Event_Concert_FK FOREIGN KEY ( Concert_ID ) REFERENCES Concert ( Concert_ID ) ;

ALTER TABLE Event ADD CONSTRAINT Event_Venue_FK FOREIGN KEY ( Venue_ID ) REFERENCES Venue ( Venue_ID ) ;

ALTER TABLE Bookings ADD CONSTRAINT FK_ASS_22 FOREIGN KEY ( Event_Event_ID ) REFERENCES Event ( Event_ID ) ;

ALTER TABLE Bookings ADD CONSTRAINT FK_ASS_23 FOREIGN KEY ( Customer_Customer_ID ) REFERENCES Customer ( Customer_ID ) ;

Answer 1

您在触发器中使用的列名与其他表不匹配。 bookings包含名为customer_customer_id和event_event_id的列，而不仅仅是customer_id和event_id。这些是PLS-00049的直接错误。

由于某种原因，event "Date"已event_date，而不是:new.evaluation。

当只有五列时，你会在审计表中插入六个值 - audit_num无处可去......

这些都是相当基本的错误。

至少假设您有一个名为CREATE OR REPLACE TRIGGER LOW_EVALUAT_1 AFTER INSERT OR UPDATE OF EVALUATION ON BOOKINGS FOR EACH ROW DECLARE CUSTOMER_NAME VARCHAR(20 CHAR); CONCERT_ID NUMBER (5,0); EVENT_DATE DATE; VENUE_ID NUMBER(5,0 ); BEGIN IF (:NEW.EVALUATION = 0) THEN SELECT CUSTOMER.CUSTOMER_ID, CONCERT.CONCERT_ID, EVENT."Date", VENUE.VENUE_ID INTO CUSTOMER_NAME,CONCERT_ID,EVENT_DATE,VENUE_ID FROM CUSTOMER, CONCERT, EVENT, VENUE WHERE CUSTOMER.CUSTOMER_ID = :NEW.CUSTOMER_CUSTOMER_ID AND EVENT.EVENT_ID = :NEW.EVENT_EVENT_ID AND CONCERT.CONCERT_ID = EVENT.CONCERT_ID; INSERT INTO AUDIT_NEW_1 VALUES (AUDIT_NUMBER.NEXTVAL, CUSTOMER_NAME, CONCERT_ID, EVENT_DATE, VENUE_ID); END IF; END; /的序列：

，这将编译

select

但我不认为它会像你期望的那样发挥作用;您需要在too_many_rows开始加入，或者获得no_data_found，您仍然可以获得该加入SELECT CUSTOMER.FULL_NAME, ...，具体取决于您的数据。根据您如何定义局部变量，它看起来也像SELECT CUSTOMER.CUSTOMER_ID, ...而不是{{1}} - 因此假设您确实希望在审计表中存储名称而不是ID，这本身有点奇怪。你真的不需要变量，你可以选择作为插入的一部分，但这是另一个主题。

Answer 2

你的DDL：

 CREATE TABLE Bookings
  (
    Event_Event_ID

但在内部触发器中你有：

EVENT.EVENT_ID = :NEW.EVENT_ID AND 应该是： EVENT.EVENT_ID = :NEW.EVENT_EVENT_ID AND

数据库中的触发错误

2 个答案: