无论我做什么,我都会在jQuery Ajax调用中遇到错误。你能弄明白我在这里错过了什么吗?
这是我的界面IShow
[ServiceContract]
public interface IShow
{
[OperationContract]
string getShow(int _showID);
}
这是我的班级
[DataContract]
public class Show
{
private string _title, _description;
private DateTime _showDate;
private int _showID;
[DataMember]
public string Title
{
get { return _title; }
set { _title = value; }
}
[DataMember]
public string Description
{
get { return _description; }
set { _description = value; }
}
[DataMember]
public DateTime ShowDate
{
get
{
return _showDate;
}
set { _showDate = value; }
}
[DataMember]
public int ShowID { get { return _showID; } set { _showID = value; } }
}
我的服务名为sShows.svc
[AspNetCompatibilityRequirements(
RequirementsMode
= AspNetCompatibilityRequirementsMode.Allowed)]
public class sShows : IShow
{
[WebInvoke(Method = "POST",
BodyStyle = WebMessageBodyStyle.WrappedRequest,
ResponseFormat = WebMessageFormat.Json,
RequestFormat = WebMessageFormat.Json
)]
public string getShow(int _showID)
{
MySqlConnection Conn = new MySqlConnection(ConfigurationManager.ConnectionStrings["CS1"].ConnectionString);
MySqlCommand cmd = new MySqlCommand();
cmd.Connection = Conn;
cmd.CommandType = System.Data.CommandType.Text;
cmd.CommandText = " SELECT s.master_id, m.showname, m.showinfo, MIN(CONCAT(s.show_date, ' ', s.show_time)) AS first_show_date, MAX(CONCAT(s.show_date, ' ', s.show_time)) AS last_show_date FROM shows s LEFT OUTER JOIN master m ON s.master_id = m.master_id WHERE (s.wt_offsale = '') AND (s.master_id = @mid) GROUP BY s.master_id ORDER BY s.show_date, s.show_time";
cmd.Parameters.AddWithValue("@mid", _showID.ToString());
MySqlDataAdapter da = new MySqlDataAdapter(cmd);
DataTable dt = new DataTable();
try
{
Conn.Open();
da.Fill(dt);
Show sh = null;
if (dt.Rows.Count > 0)
{
sh = new Show
{
Title = dt.Rows[0].ItemArray[1].ToString(),
Description = dt.Rows[0].ItemArray[2].ToString()
};
}
// return sh;
return JsonConvert.SerializeObject(sh, Formatting.Indented);
}
catch (Exception)
{
throw;
}
finally
{
Conn.Close();
dt.Dispose();
da.Dispose();
}
}
}
最后这是我的web.config(在服务项目中)
<!-- To avoid disclosing metadata information, set the values below to false before deployment -->
<serviceMetadata httpGetEnabled="true" httpsGetEnabled="true"/>
<!-- To receive exception details in faults for debugging purposes, set the value below to true. Set to false before deployment to avoid disclosing exception information -->
<serviceDebug includeExceptionDetailInFaults="true"/>
</behavior>
</serviceBehaviors>
<endpointBehaviors>
<behavior name="WebBehaviour">
<!--<enableWebScript/>-->
<webHttp defaultOutgoingResponseFormat="Json"/>
<!--<webHttp/>-->
</behavior>
</endpointBehaviors>
</behaviors>
<protocolMapping>
<add binding="basicHttpsBinding" scheme="https" />
</protocolMapping>
这是我的Ajax Call
jQuery.ajax({
type: "POST",
url: "http://localhost:10677/sShows.svc/Web/getShow",
data: "{_showID: 288}",
contentType: "application/json; charset=utf-8",
dataType: "json",
processData: true,
success: function (result) {
alert(result.d.Title);
},
error: function (result) {
alert(result.statusText);
console.log("Service = " + result.d);
}
});
无论我做什么,我都会得到&#34;错误&#34;在客户端上作为警报。请问你能检查一下究竟是什么问题???
由于
更新 这是我从小提琴手那里得到的东西
OPTIONS http://localhost:10677/sShows.svc/Web/getShow HTTP/1.1
Host: localhost:10677
Connection: keep-alive
Access-Control-Request-Method: POST
Origin: http://localhost:2299
User-Agent: Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/33.0.1750.154 Safari/537.36
Access-Control-Request-Headers: accept, content-type
Accept: */*
DNT: 1
Referer: http://localhost:2299/SimiArts/events.aspx
Accept-Encoding: gzip,deflate,sdch
Accept-Language: en-US,en;q=0.8,ur;q=0.6
HTTP/1.1 405 Method Not Allowed
Cache-Control: private
Allow: POST
Content-Length: 1565
Content-Type: text/html; charset=UTF-8
Server: Microsoft-IIS/8.0
X-AspNet-Version: 4.0.30319
X-SourceFiles: =?UTF-8?B?QzpcVXNlcnNcQXRoYXJBbmlzXERvY3VtZW50c1xNRUdBXFBQSCBKb2JzXFNoYXVuXFdjZlNlcnZpY2UxXHNTaG93cy5zdmNcV2ViXGdldFNob3c=?=
X-Powered-By: ASP.NET
Date: Tue, 08 Apr 2014 16:12:24 GMT
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Service</title>
<style>BODY { color: #000000; background-color: white; font-family: Verdana; margin-left: 0px; margin-top: 0px; } #content { margin-left: 30px; font-size: .70em; padding-bottom: 2em; } A:link { color: #336699; font-weight: bold; text-decoration: underline; } A:visited { color: #6699cc; font-weight: bold; text-decoration: underline; } A:active { color: #336699; font-weight: bold; text-decoration: underline; } .heading1 { background-color: #003366; border-bottom: #336699 6px solid; color: #ffffff; font-family: Tahoma; font-size: 26px; font-weight: normal;margin: 0em 0em 10px -20px; padding-bottom: 8px; padding-left: 30px;padding-top: 16px;} pre { font-size:small; background-color: #e5e5cc; padding: 5px; font-family: Courier New; margin-top: 0px; border: 1px #f0f0e0 solid; white-space: pre-wrap; white-space: -pre-wrap; word-wrap: break-word; } table { border-collapse: collapse; border-spacing: 0px; font-family: Verdana;} table th { border-right: 2px white solid; border-bottom: 2px white solid; font-weight: bold; background-color: #cecf9c;} table td { border-right: 2px white solid; border-bottom: 2px white solid; background-color: #e5e5cc;}</style>
</head>
<body>
<div id="content">
<p class="heading1">Service</p>
<p>Method not allowed.</p>
</div>
</body>
</html>
答案 0 :(得分:2)
"{_showID: 288}"
不是valid JSON。 "{\"_showID\": 288}"
可能就是你要找的东西。或者,更好的是,创建一个普通对象,让jQuery执行JSON序列化。
data: { _showId: 288 },
OPTIONS调用是由跨站点脚本调用引起的。在同一主机和端口上创建网站和服务,或使用JSONP建议的jQuery $.ajax(), $.post sending "OPTIONS" as REQUEST_METHOD in Firefox回调。