弹出窗口在外部触摸时解除

时间:2014-04-08 14:39:54

标签: android popup alertdialog

我搜索了很多但没有得到答案......

这是我想要做的......

 LayoutInflater inflater = (LayoutInflater)screen.getSystemService(screen.LAYOUT_INFLATER_SERVICE);
                    layout =  inflater.inflate(R.layout.snap_log_viewer,null);

                    AlertDialog.Builder builder = new AlertDialog.Builder(SnapLog_Activity.this);


                    builder.setView(layout);

                    AlertDialog alertDialog = builder.create(); 
 alertDialog.setCancelable(true);
                    alertDialog.setCanceledOnTouchOutside(true);
                    alertDialog.show();

 WindowManager.LayoutParams lp = new WindowManager.LayoutParams();

                    Window window = alertDialog.getWindow();
                    alertDialog.getWindow().addFlags(WindowManager.LayoutParams.FLAG_NOT_TOUCH_MODAL);
                    lp.copyFrom(window.getAttributes());

                    lp.width = WindowManager.LayoutParams.MATCH_PARENT;
                    lp.height = WindowManager.LayoutParams.WRAP_CONTENT;
                    window.setAttributes(lp);

并且想在外面碰到时解雇...

尝试了

setBackgroundDrawable(new BitmapDrawable());
setOutsideTouchable(true);

但没有得到ouptput ..

2 个答案:

答案 0 :(得分:1)

你不应该添加标志,并且在构建之后搞乱如何构建alertDialog。 怎么样尝试这一切:

AlertDialog alertDialog = new AlertDialog.Builder(**CURRENTACTIVITY**.this).create();
alertDialog.setTitle(getString(R.string.titleString));
alertDialog.setMessage(text);
alertDialog.setButton("OK", new DialogInterface.OnClickListener() {

@Override
public void onClick(DialogInterface dlg, int arg1) 
{
dlg.dismiss();
}
     });


alertDialog.setCancelable(true);
alertDialog.setCanceledOnTouchOutside(true);
alertDialog.show();
            return;

            }
        });

答案 1 :(得分:0)

在显示之前将cancelable设置为true。

alertDialog.setCancelable(true);
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