Question

我试图在上传文件时获取文件大小。我的最终目标是尝试获取上传速度，但在我的while循环中，我得到一个异常调用＆＃34; OpenRead＆＃34;用＆＃34; 1＆＃34;参数：＆＃34;远程服务器返回错误：（550）文件不可用（例如，找不到文件，没有访问权限。）

请参阅以下代码

$uploadRemoteFile = "Remote URI"
$ftpuname = "UserName"
$ftppassword = 'Password'

function upload-ftp{
    $File = "$env:TEMP\something.exe"
    $webclient = New-Object System.Net.WebClient
    $webclient.Credentials = New-Object System.Net.NetworkCredential($ftpuname,$ftppassword); 
    $uri = New-Object System.Uri($uploadRemoteFile)
    $webclient.UploadFileAsync($Uri, $File)
    $arrayftp = @()
    Function Get-newfilesize{
        $webclientRead = New-Object System.Net.WebClient;
        $webclientRead.Credentials = New-Object System.Net.NetworkCredential($ftpuname,$ftppassword); 
        [void]$webclientRead.OpenRead($uri);
        [Int64]$bytes_total= ($webclientRead.ResponseHeaders["Content-Length"])
        $webclientsize = ($bytes_total.ToString());
        $webclientsize
    }
    while ($webclient.IsBusy){
        $oldftpfile = Get-newfilesize;

        $oldftpdate = Get-Date;

        Start-Sleep -Milliseconds 1

        $newftpfile = Get-newfilesize;
        $newftpdate = Get-Date;

        $ftpsizediff = $newftpfile - $oldftpfile;
        $ftptimediff = $newftpdate - $oldftpdate;

        $totalftpdiff = $ftpsizediff / $ftptimediff.totalseconds;
        $totalftpdiff  | foreach {
            if ($_ -gt 0){$arrayftp += $_ }
        }
    }
    $testftpcap= New-Object psobject -Property @{"Upload Speed" =((($arrayftp | measure -Average).Average/1MB)* 10)}
    $testftpcap | Export-csv -NoTypeInformation -Path $env:TEMP\ftpspeed.csv
}

由于

Answer 1

不完全是您问题的直接答案，但您可以使用Powershell FTP模块 - 效果很好，也有进度条... （http://gallery.technet.microsoft.com/scriptcenter/PowerShell-FTP-Client-db6fe0cb）

上传文件时检索文件大小550错误

1 个答案: