我将webapp从struts 2.0移植到2.3。我无法使DynamicMethodInvocation工作。
我有一个使用add()
方法的动作类。 在register!add.shtml
上提交表单不会执行此方法。
我找不到任何理由。
以下是我使用的罐子:
struts2-core-2.3.16.jar
xwork-core-2.3.16.jar
struts2-spring-plugin-2.3.16.jar
这里是struts.xml
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
"http://struts.apache.org/dtds/struts-2.3.dtd">
<struts>
<constant name="struts.objectFactory" value="spring"/>
<constant name="struts.devMode" value="true"/>
<constant name="struts.url.includeParams" value="none" />
<constant name="struts.enable.DynamicMethodInvocation" value="true"/>
<constant name="struts.action.extension" value="shtml"/>
<package name="item" extends="struts-default" strict-method-invocation="true">
<action name="register" class="profileAction">
<!--<result>/WEB-INF/jsp/register.jsp</result>-->
<result name="success">/WEB-INF/jsp/register_success.jsp</result>
<result name="input">/WEB-INF/jsp/register.jsp</result>
<result name="error">/WEB-INF/jsp/register.jsp</result>
<allowed-methods>execute,add,save</allowed-methods>
</action>
还有一个简单的struts-beans.xml
。没有其他文件,例如.properties
。
任何?
PS这里是动作代码。但我认为这不重要。我试过在第一行放一个断点。但是调试器并没有达到目的。
public String add() {
try {
StringBuilder sb = new StringBuilder();
sb.append("<person>\n")
.append("<fullname>").append(getLastName()).append(" ").append(getFirstName()).append("</fullname>\n")
.append("<login>").append(getLogin()).append("</login>\n")
.append("<email>").append(getLogin()).append("</email>\n")
.append("<phone>").append(getPhone()).append("</phone>\n")
.append("</person>\n");
URL url = new URL(getCreatePersonURL());
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/xml; charset=utf8");
OutputStreamWriter wr= new OutputStreamWriter(connection.getOutputStream());
wr.write(sb.toString());
InputStream content = connection.getInputStream();
BufferedReader in = new BufferedReader(new InputStreamReader(content));
String line;
if ((line = in.readLine()) != null)
if (!line.equalsIgnoreCase("<status>OK</status>")) {
addActionError("Регистрация в данный момент не возможна"); // TODO обработка ошибок от zayavkaapi
return Action.ERROR;
}
} catch (IOException e) {
addActionError("Регистрация в данный момент не возможна"); // TODO обработка ошибок от zayavkaapi
return Action.ERROR;
}
Customer c = new Customer();
c.setKeyword(getKeyphrase());
c.setPassword(getPassword());
c.setLogin(getLogin());
c.setEmail(getEmail());
ContactPerson cp = new ContactPerson();
cp.setFirstName(getFirstName());
cp.setLastName(getLastName());
cp.setMiddleName(getMiddleName());
ArrayList<ContactInfo> cil = new ArrayList<ContactInfo>();
ContactInfo ci = new ContactInfo();
ci.setContactInfoTypeId("ADDRESS");// Адрес
ci.setCountryId(getCountry());
ci.setField2(getCity());
cil.add(ci);
ci = new ContactInfo();
ci.setContactInfoTypeId("PHONE");// Телефон
//String[] strings = getPhone().split(" ");
ci.setField1(getCountryCode());
ci.setField2(getCityCode());
ci.setField3(getPhone());
ci.setField4(getOfficePhone());
//if (strings.length > 3)
cil.add(ci);
ci = new ContactInfo();
ci.setContactInfoTypeId("EMAIL");// e-mail
ci.setField1(getEmail());
cil.add(ci);
cp.setContactInfoList(cil);
c.setMainContactPerson(cp);
ArrayList<ContactPerson> cpl = new ArrayList<ContactPerson>();
cpl.add(cp);
c.setContactPersons(cpl);
Long customerId = customerManager.createCustomer(c);
customer = customerManager.getCustomerById(customerId);
User user = new User(getLogin(), Md5Calc.MD5(getPassword()) , true, true, true, true, new GrantedAuthority[]{new GrantedAuthorityImpl("ROLE_CUSTOMER")});
UsernamePasswordAuthenticationToken result = new UsernamePasswordAuthenticationToken(user, getLogin(), user.getAuthorities());
SecurityContextHolder.getContext().setAuthentication(result);
return Action.SUCCESS;
}
答案 0 :(得分:1)
在此处发布代码建议我将@SkipValidation
注释添加到add()
方法。它开始执行了。正如汤姆所说,我确实遇到了一个未输出到错误部分的验证错误。这使得该方法不再被执行。