我有一个textview,其中我正在显示论坛帖子的内容,该帖子使用rte在网站上输入,内容涉及图像,类型为web url和类型Base64
。默认实现Html.fromHtml用小方块替换所有img
标签..
我在SO上寻找使用Html.fromHtml方法从url加载图像的解决方案,结果有办法做到这一点,我们可以将ImageGetter传递给函数..我找到了this很棒的答案网址获取部分但当内容的图片为Base64
时,此操作会失败并崩溃应用程序..
我看了一种为Base64
src创建图像的方法,但没有一个解决方案正在运行,如果有人已经实现了整个解决方案,那就太棒了。如果某人只有Base64
部分,请提供我将整合两者的内容..
答案 0 :(得分:14)
最后花了好几个小时后,我找到了Base64
图片的解决方案..我在这里发布完整的解决方案..
我再次感谢https://stackoverflow.com/a/15617341/1114536的基本答案。
原来我使用的答案是参考只是this asnwer的副本..
<强> URLDrawable.java 强>
import android.graphics.Canvas;
import android.graphics.drawable.BitmapDrawable;
import android.graphics.drawable.Drawable;
public class URLDrawable extends BitmapDrawable {
// the drawable that you need to set, you could set the initial drawing
// with the loading image if you need to
protected Drawable drawable;
@Override
public void draw(Canvas canvas) {
// override the draw to facilitate refresh function later
if(drawable != null) {
drawable.draw(canvas);
}
}
}
<强> URLImageParser.java 强>
import java.io.InputStream;
import java.net.URL;
import android.content.Context;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.graphics.drawable.BitmapDrawable;
import android.graphics.drawable.Drawable;
import android.os.AsyncTask;
import android.text.Html.ImageGetter;
import android.util.Base64;
import android.view.View;
public class URLImageParser implements ImageGetter {
Context context;
View container;
public URLImageParser(View container, Context context) {
this.context = context;
this.container = container;
}
public Drawable getDrawable(String source) {
if(source.matches("data:image.*base64.*")) {
String base_64_source = source.replaceAll("data:image.*base64", "");
byte[] data = Base64.decode(base_64_source, Base64.DEFAULT);
Bitmap bitmap = BitmapFactory.decodeByteArray(data, 0, data.length);
Drawable image = new BitmapDrawable(context.getResources(), bitmap);
image.setBounds(0, 0, 0 + image.getIntrinsicWidth(), 0 + image.getIntrinsicHeight());
return image;
} else {
URLDrawable urlDrawable = new URLDrawable();
ImageGetterAsyncTask asyncTask = new ImageGetterAsyncTask(urlDrawable);
asyncTask.execute(source);
return urlDrawable; //return reference to URLDrawable where We will change with actual image from the src tag
}
}
public class ImageGetterAsyncTask extends AsyncTask<String, Void, Drawable> {
URLDrawable urlDrawable;
public ImageGetterAsyncTask(URLDrawable d) {
this.urlDrawable = d;
}
@Override
protected Drawable doInBackground(String... params) {
String source = params[0];
return fetchDrawable(source);
}
@Override
protected void onPostExecute(Drawable result) {
urlDrawable.setBounds(0, 0, 0 + result.getIntrinsicWidth(), 0 + result.getIntrinsicHeight()); //set the correct bound according to the result from HTTP call
urlDrawable.drawable = result; //change the reference of the current drawable to the result from the HTTP call
URLImageParser.this.container.invalidate(); //redraw the image by invalidating the container
}
public Drawable fetchDrawable(String urlString) {
try {
InputStream is = (InputStream) new URL(urlString).getContent();
Drawable drawable = Drawable.createFromStream(is, "src");
drawable.setBounds(0, 0, 0 + drawable.getIntrinsicWidth(), 0 + drawable.getIntrinsicHeight());
return drawable;
} catch (Exception e) {
return null;
}
}
}
}
<强>用法:强>
TextView comment_content_container = ((TextView)findViewById(R.id.comment_content));
comment_content_container.setText(Html.fromHtml(comment.content, new URLImageParser(comment_content_container, this), null));
如果有人知道Base64
更好的正则表达式,请回复我会更新答案..
答案 1 :(得分:4)
作为Rajat Singhal的回答(对不起,我没有足够的声誉发表评论):
我的drawable尺寸错误(它更小),因为drawables考虑了屏幕密度。为了保留原始图像大小,我最终在fetchDrawable方法中执行了此操作:
public Drawable fetchDrawable(String urlString) {
try {
InputStream is = (InputStream) new URL(urlString).getContent();
Bitmap bmp = BitmapFactory.decodeStream(is);
Drawable drawable = new BitmapDrawable (context.getResources(), bmp);
drawable.setBounds(0, 0, drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight());
return drawable;
} catch (Exception e) {
return null;
}
}
答案 2 :(得分:1)
我只是想从Rajat的答案中确定图像的大小,图像将占据textview的整个宽度,并保持高度的长宽比。这是我的更新:
public Drawable getDrawable(String source)
{
if(source.matches("data:image.*base64.*"))
{
String base_64_source = source.replaceAll("data:image.*base64", "");
byte[] data = Base64.decode(base_64_source, Base64.DEFAULT);
Bitmap bitmap = BitmapFactory.decodeByteArray(data, 0, data.length);
Drawable image = new BitmapDrawable(context.getResources(), bitmap);
float ratio = container.getWidth() / image.getIntrinsicWidth();
int width = container.getWidth();
int height = Math.round(image.getIntrinsicHeight() * ratio);
image.setBounds(0, 0, width, height);
return image;
}
else
{
....
}
}
public class ImageGetterAsyncTask extends AsyncTask<String, Void, Drawable>
{
....
@Override
protected void onPostExecute(Drawable result)
{
if(result != null)
{
float ratio = container.getWidth() / result.getIntrinsicWidth();
int width = container.getWidth();
int height = Math.round(result.getIntrinsicHeight() * ratio);
urlDrawable.setBounds(0, 0, width, height); //set the correct bound according to the result from HTTP call
urlDrawable.drawable = result; //change the reference of the current drawable to the result from the HTTP call
URLImageParser.this.container.invalidate(); //redraw the image by invalidating the container
}
}
public Drawable fetchDrawable(String urlString)
{
try
{
InputStream is = (InputStream) new URL(urlString).getContent();
Bitmap bmp = BitmapFactory.decodeStream(is);
Drawable drawable = new BitmapDrawable (context.getResources(), bmp);
float ratio = container.getWidth() / drawable.getIntrinsicWidth();
int width = container.getWidth();
int height = Math.round(drawable.getIntrinsicHeight() * ratio);
drawable.setBounds(0, 0, width, height);
return drawable;
}
catch (Exception e)
{
return null;
}
}
}
}
但是,Ranjat的解决方案仅显示1张图像。如果您想显示多张图像,则需要在ImageSpan
内使用SpannableStringBuilder
,如果需要示例,请在评论中告诉我。