Question

我的代码会在实际日期增加+1天。

var date = '30 Apr 2010';
var actual_date = new Date(date);
var final_date = new Date(actual_date.getFullYear(), actual_date.getMonth(), actual_date.getDate()+1);

我现在想要达到的目的是避免在实际日期是星期五的周末（周六和周日）。

Normal midweek example: 
tuesday, 5th -> wednesday, 6th

Weekend example:
friday, 6th -> monday, 9th

Answer 1

测试actual_date.getDay()，即星期几。如果5（星期五）加3天，如果6（星期六）加2天，则另外加1天。

Answer 2

您可以在循环中添加一天，并检查工作日是0（=太阳）还是6（=星期六）：

d = new Date(2014, 3, 4)   // Fri Apr 04

do {
   d.setDate(d.getDate() + 1)
} while(d.getDay() == 0 || d.getDay() == 6);

console.log(d); // Mon Apr 07

Answer 3

试试：

var date = '30 Apr 2010';
var final_date = actual_date = new Date(date);

do {
  final_date = new Date(final_date.getFullYear(), final_date.getMonth(), final_date.getDate()+1);
  var day = final_date.getDay();
} while (day == 6 || day == 0); // (6 is saturday, 0 is sunday)

输出：

Mon May 03 2010 00:00:00 GMT+0200 (CEST)

Answer 4

尝试

var date = '30 Apr 2010';
var actual_date = new Date(date);
var final_date = new Date(actual_date);
final_date.setDate(final_date.getDate() + 1 + (actual_date.getDay() > 4 ? 7 - actual_date.getDay() : 0));

演示：Fiddle

Answer 5

var final_date = new Date(
    actual_date.getFullYear(), 
    actual_date.getMonth(), 
    actual_date.getDay() === 5 // Friday
      ? actual_date.getDate()+3 
      : actual_date.getDay() === 6 // Saturday 
      ? actual_date.getDate() + 2 
      : actual_date.getDate() + 1 // others
);

Answer 6

以下示例使用momentjs

var aDate = moment("22. Apr. 2011");  // your starting date
var DAY_IN_MSEC = 1000 * 60 * 60 * 24; // a day represented in milliseconds
var fiveDays = 5 * DAY_IN_MSEC; // five days


var newDate = moment(aDate + fiveDays); // add your 5 days to original date
var dayOfWeek = newDate.weekday(); // get the index of the day  *locale dependent
if (dayOfWeek >= 5) {             // is saturday, sunday *locale dependent
   var daysToMonday = 7 - dayOfWeek;
   newDate += daysToMonday * DAY_IN_MSEC; // add the difference needded until Monday
   newDate = moment(newDate); // transform the msecs in a moment object
}

alert('voila!');

Answer 7

这应该有效：

var date = '30 Apr 2010';
var actual_date = new Date(date);

// Add 3 days if friday, 2 days if saturday otherwise add 1 day.
var daysToAdd = actual_date.getDay() === 5 ? 3 : actual_date.getDay() === 6 ? 2 : 1;

var final_date = new Date(actual_date.getFullYear(), actual_date.getMonth(), actual_date.getDate() + daysToAdd);

或者更详细：

var daysToAdd = 1;
if (actual_date.getDay() === 5)
  daysToAdd = 3;
else if (actual_date.getDate() === 6)
  daysToAdd = 2;

Answer 8

使用getDay()功能检查其是否为5（星期五）。然后添加3天。请参阅小提琴：http://jsfiddle.net/JLGxQ/

var date = '30 Apr 2010';
var actual_date = new Date(date);

if(actual_date.getDay() == 5){
     x = 3;   
} else {
     x = 1;   
}

var final_date = new Date(actual_date.getFullYear(), actual_date.getMonth(), actual_date.getDate()+x);

添加一天到晚 - 避免周末（周六，周日）

8 个答案: