我想计算两个位置之间的距离(即用户的当前位置和目的地位置)。我在我的数据库和当前位置有目的地位置的纬度和经度(我通过位置管理器类找到)。 我需要在列表视图中显示该计算的距离。 如果我通过位置类的任何数学公式或 DistanceTo()和DistanceBetween()方法计算它,那么我就不会在地图上获得准确的距离。 如果我通过Google的距离矩阵API计算距离,那么它需要花费太多时间来计算距离并加载列表。(因为有很多目的地位置有一个当前位置的用户) 请有人建议我最好的计算方法.. 我在最近几天遇到了这个问题。帮助我 提前谢谢......
答案 0 :(得分:2)
最后经过大量的谷歌搜索我完成了我的任务。我通过异步任务尝试了它。 这是我的代码..
public View getView(int position, View convertView, ViewGroup Parent)
{
final ViewHolder holder=new ViewHolder();
View view=convertView;
if (view==null) {
convertView= inflater.inflate(R.layout.layout_row, null);
}
holder.textdistance=(TextView) convertView.findViewById(R.id.textView_Distance);
holder.position = position;
if(data.size()<=0)
{
Toast.makeText(activity, "No data", Toast.LENGTH_LONG).show();
}
else
{
**new ThumbnailTask(position, holder)
.executeOnExecutor(AsyncTask.THREAD_POOL_EXECUTOR, null);**
}
return convertView;
}
//Thumbnail Class
private static class ThumbnailTask extends AsyncTask {
private int mPosition;
private ViewHolder mHolder;
public ThumbnailTask(int position, ViewHolder holder) {
mPosition = position;
mHolder = holder;
}
/* (non-Javadoc)
* @see android.os.AsyncTask#doInBackground(Params[])
*/
@Override
protected Object doInBackground(Object... params) {
// TODO Auto-generated method stub
String Distance="3";
String uri="https://maps.googleapis.com/maps/api/distancematrix/json? origins=(Your source Addres like XYZ,South Delhi-110064),&mode=deriving&sensor=false&key=(Your API Key)";
String result= GET(uri);
Log.d("result","res="+result);
try {
//jArray = new JSONObject(result);
JSONObject object = (JSONObject) new JSONTokener(result).nextValue();
JSONArray array = object.getJSONArray("rows");
// Log.d("JSON","array: "+array.toString());
//Routes is a combination of objects and arrays
JSONObject rows = array.getJSONObject(0);
//Log.d("JSON","routes: "+routes.toString());
JSONArray elements = rows.getJSONArray("elements");
// Log.d("JSON","legs: "+legs.toString());
JSONObject steps = elements.getJSONObject(0);
//Log.d("JSON","steps: "+steps.toString());
JSONObject distance = steps.getJSONObject("distance");
Log.d("JSON","distance: "+distance.toString());
Distance = distance.getString("text");
Log.d("final value","tot dis="+Distance);
JSONObject duration=steps.getJSONObject("duration");
// MyDuration=duration.getString("text");
}
catch(JSONException e)
{
Log.d("JSONEXCeption","my exce"+e.getMessage());
}
return Distance;
}
@Override
protected void onPostExecute(Object result) {
// TODO Auto-generated method stub
mHolder.textdistance.setText(result.toString());
}
}
//method to execute Url
private static String GET(String url)
{
InputStream inputStream = null;
String result = "";
try {
// create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// make GET request to the given URL
HttpResponse httpResponse = httpclient.execute(new HttpGet(url));
// receive response as inputStream
inputStream = httpResponse.getEntity().getContent();
// convert inputstream to string
if(inputStream != null)
result = convertInputStreamToString(inputStream);
// Log.i("Result",result);
else
result = "Did not work!";
} catch (Exception e) {
Log.d("InputStream", "hello"+e);
}
return result;
}
private static String convertInputStreamToString(InputStream inputStream) throws IOException{
BufferedReader bufferedReader = new BufferedReader( new InputStreamReader(inputStream));
String line = "";
String result = "";
while((line = bufferedReader.readLine()) != null)
result += line;
inputStream.close();
return result;
}
}
参考链接是 -
http://lucasr.org/2012/04/05/performance-tips-for-androids-listview/ https://developers.google.com/maps/documentation/distancematrix/
我不善于解释,但我正在努力。希望它能帮助像我这样的其他人,因为我遇到了这个任务。
答案 1 :(得分:1)
试试这个。我在旧的应用程序中添加它。它对我有用。通过Initialize R=Radius
的方式。仔细阅读this文章
public double CalculationByDistance(GeoPoint StartP, GeoPoint EndP) {
double lat1 = StartP.getLatitudeE6()/1E6;
double lat2 = EndP.getLatitudeE6()/1E6;
double lon1 = StartP.getLongitudeE6()/1E6;
double lon2 = EndP.getLongitudeE6()/1E6;
double dLat = Math.toRadians(lat2-lat1);
double dLon = Math.toRadians(lon2-lon1);
double a = Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2)) *
Math.sin(dLon/2) * Math.sin(dLon/2);
double c = 2 * Math.asin(Math.sqrt(a));
return Radius * c;
}
答案 2 :(得分:1)
如果有很多地方使用循环。只需几行代码即可完成此任务:
Location l1=new Location("One");
l1.setLatitude(location.getLatitude());
l1.setLongitude(location.getLongitude());
Location l2=new Location("Two");
l2.setLatitude(Double.parseDouble(frnd_lat));
l2.setLongitude(Double.parseDouble(frnd_longi));
float distance_bw_one_and_two=l1.distanceTo(l2);