此代码警告'test 1',然后警告8!
uri = 'http://www.scriptcopy.com/';
compareuris = new Array();
compareuris[0] = 'http://www.scriptcopy.com/';
compareuris[1] = 'https://www.scriptcopy.com/';
compareuris[2] = 'http://www.www.scriptcopy.com/';
compareuris[3] = 'https://www.www.scriptcopy.com/';
compareuris[4] = 'http://scriptcopy.com/';
compareuris[5] = 'https://scriptcopy.com/';
compareuris[6] = 'http://www.scriptcopy.com/';
compareuris[7] = 'https://www.scriptcopy.com/';
searchuri = 'http://www.google.com/search?';
searchuri += 'q='+ encodeURIComponent(uri) +'&btnG=Search+Directory&hl=en&cat=gwd%2FTop';
req = new XMLHttpRequest();
req.open('GET', searchuri, true);
req.onreadystatechange = function (aEvt) {
if (req.readyState == 4) {
if(req.status == 200) {
searchcontents = req.responseText;
parsedHTML = sc_HTMLParser(searchcontents);
sitefound = sc_sitefound(compareuris, parsedHTML);
}
}
}
req.send(null);
function sc_HTMLParser(aHTMLString){
var parseDOM = content.document.createElement('div');
parseDOM.appendChild(Components.classes['@mozilla.org/feed-unescapehtml;1']
.getService(Components.interfaces.nsIScriptableUnescapeHTML)
.parseFragment(aHTMLString, false, null, parseDOM));
return parseDOM;
}
function sc_sitefound(compareuris, parsedHTML) {
gclasses = parsedHTML.getElementsByClassName('g');
alert('test 1');
for (i = 0; i < gclasses.length; i++) {
alert(i);
gclass = gclasses[i];
atags = gclass.getElementsByTagName('a');
tag1 = atags[0];
hrefattribute1 = tag1.getAttribute('href');
uri1 = hrefattribute1;
compareduris = sc_compareuris(uri1, compareuris);
alert('test 2');
if (compareduris) {
sitefound = uri1;
return sitefound;
alert('test 3');
}
alert('test 4');
}
return null;
}
function sc_compareuris(uri, compareuris) {
for (i = 0; i < compareuris.length; i++) {
compareuri = compareuris[i];
if (uri == compareuri) {
return true;
}
}
return false;
}
聚焦:
alert('test 1');
for (i = 0; i < gclasses.length; i++) {
alert(i);
为什么以及如何解决?
答案 0 :(得分:4)
之前我在IE中遇到过这样的问题。您应该始终使用var
循环中的for
来确保i
是本地范围的:
alert('test 1');
for (var i = 0; i < gclasses.length; i++) {
alert(i);
// etc...
}
除非您事先在同一范围内声明变量:
var i;
alert('test 1');
for (i = 0; i < gclasses.length; i++) {
alert(i);
// etc...
}
另见:
Variable scope in Javascript for loop
http://developer.mozilla.org/En/Core_JavaScript_1.5_Reference/Statements/Var
答案 1 :(得分:1)
你有没有其他警报,没有粘贴在那里?如果您将其更改为:
,该怎么办?alert('test 1, gclasses.length = '+gclasses.length);
for (var i = 0; i < gclasses.length; i++) {
alert(i);
我想知道该循环是否正在执行?
答案 2 :(得分:1)
在您使用它的每个函数中本地声明变量(在这种情况下为i
)。如果为变量赋值(即使使用for循环),它也会变为全局变量,并且可能会同时运行其他函数。