Question

美好的一天

我返回了以下结果集：

financeYearEnd          FromDate    ToDate      ClientPortfolioCode
2013-12-31 00:00:00.000 2014-01-01  2014-01-31  C1
2013-12-31 00:00:00.000 2014-01-01  2014-01-31  C2
2012-12-31 00:00:00.000 2013-12-01  2013-12-31  C1
2012-12-31 00:00:00.000 2013-12-01  2013-12-31  C2

我需要做的是：

我需要比较所有C1 Fields的financeYearEnd（总是只有两个），看看它们是否彼此不同

 2013-12-31 00:00:00.000    2014-01-01  2014-01-31  C1
 2012-12-31 00:00:00.000    2013-12-01  2013-12-31  C1

如图所示，financeYearEnd确实不同，所以我需要将该结果作为一行存储在临时表中。

这需要针对所有不同的ClientPortfolioCodes（总是以两个为一组出现）进行。

如何实现这一目标？

我试过select distinct .. - 没有工作。它返回了我的所有行

编辑 -

WITH cteCompareTopTwoYears
AS (
    SELECT TOP (
            SELECT COUNT(*) * 2
            FROM #ClientPortFolios
            ) FinancialYearEnd AS financeYearEnd
        ,FromDate
        ,ToDate
        ,CA.ClientPortfolioCode
    FROM rpt.F3_fn_ClientPortfolios_CapitalAccount_IncludingYTD CA
    WHERE (
            (
                CA.FromDate = (DATEADD(m, - 1, @FromDate))
                AND CA.ToDate = (DATEADD(m, - 1, @ToDate))
                )
            OR (
                CA.FromDate = @FromDate
                AND CA.ToDate = @ToDate
                )
            )
        AND (
            CA.ClientPortFolioCode IN (
                SELECT ClientPortfolioCode
                FROM #ClientPortfolios
                )
            )
    ORDER BY FromDate DESC
    )
SELECT *
FROM cteCompareTopTwoYears c

Answer 1

也许在ROW_NUMBER的帮助下，例如：

WITH CTE AS
(
    SELECT financeYearEnd, FromDate, ToDate, ClientPortfolioCode,
           rn = row_Number () OVER (Partition By ClientPortfolioCode
                                    Order By financeYearEnd ASC)
    FROM dbo.TableName
)
SELECT financeYearEnd, FromDate, ToDate, ClientPortfolioCode
FROM CTE
WHERE rn > 1

Demo

SQL中两行的比较

1 个答案: