Question

我有一个edittext，如果输入的输入数字为100000，则结果必须为100.000，如果我输入的输入为1000000，则结果必须为1.000.000是.。

从最后一个到开头的每3个字符后必须有一个＆＃34; tambah = (EditText)rootView.findViewById(R.id.total); tambah.setOnFocusChangeListener(new OnFocusChangeListener(){ public void onFocusChange(View v, boolean hasFocus) { // ... }＆＃34;

这是我的代码：

{{1}}

Answer 1

您应该使用'java.text.NumberFormat'：

java.text.NumberFormat nf = java.text.NumberFormat.getInstane();
nf.setMaximumFractionDigits(0);
String formattedNumber = nf.format(Integer.parseInt(edittext.getText());

Answer 2

使用editText.setOnTextChangeListener（）并检查每次位置是否为3的倍数。（点）那里..

Answer 3

这是我用来输入美元的东西。它确保始终只有小数点后2位。您应该可以通过删除$ sign来使其适应您的需求。

amountEditText.setRawInputType(Configuration.KEYBOARD_12KEY);
amountEditText.addTextChangedListener(new TextWatcher() {
    public void afterTextChanged(Editable s) {}
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {}

public void onTextChanged(CharSequence s, int start, int before, int count) {
    if(!s.toString().matches("^\\$(\\d{1,3}(\\,\\d{3})*|(\\d+))(\\.\\d{2})?$"))
    {
        String userInput= ""+s.toString().replaceAll("[^\\d]", "");
        StringBuilder cashAmountBuilder = new StringBuilder(userInput);

        while (cashAmountBuilder.length() > 3 && cashAmountBuilder.charAt(0) == '0') {
            cashAmountBuilder.deleteCharAt(0);
        }
        while (cashAmountBuilder.length() < 3) {
            cashAmountBuilder.insert(0, '0');
        }
        cashAmountBuilder.insert(cashAmountBuilder.length()-2, '.');
        cashAmountBuilder.insert(0, '$');

        amountEditText.setText(cashAmountBuilder.toString());
        // keeps the cursor always to the right
        Selection.setSelection(amountEditText.getText(), cashAmountBuilder.toString().length());

    }

}
});

Answer 4

首先使用%,d格式格式化您的字符串，然后将所有（，）替换为（。），如下所示...

    String formatedString = (String.format("%,d", 1000000)).replace(',', '.');

    Log.d("Fomated String", formatedString);

<强>输出：

 D/Fomated String(20323): 1.000.000

Answer 5

如何使用以下循环来完成它。

String Number=1000000;
final int THREE=3;
int noOfPoints,length,Start=0,End=0;

length=Number.length();
noOfPoints=length%THREE;
if(noOfPoints*THREE==length)
noOfPoints--;
String OutPut="";

for(int Count=0;Count<=noOfPoints;Count++)
{
Start=End;
if(Count==0)
End=length-(THREE*noOfPoints);
else
End=Start+THREE;

if(Count!=noOfPoints)
OutPut+=Number.substring(Start,End)+".";
else
OutPut+=Number.substring(Start,End);
}

Answer 6

这是另一个答案。希望它有用，简单，它会格式化给定参数的大小（格式化，在示例调用时）看看。

/ ** * * @param输入 * @param formatsize * @return * /

public String format(String input, int formatsize) {

    String formattedNumberString = "";
    int len = input.length();

    if (len < formatsize)
        return input;

    if (formatsize < 2) {
        System.out.println("Opppps");
        return "";
    }

    for (int i = 0; i < len; i += formatsize) {
        if (i < formatsize) {
            formattedNumberString = input.substring(input.length()
                    - formatsize - 1, input.length() - 1);
        } else {

            if (len - i <= formatsize) {
                formattedNumberString = input + "." + formattedNumberString;
            } else {
                formattedNumberString = input.substring(input.length()
                        - formatsize - 1, input.length() - 1)
                        + "." + formattedNumberString;
            }
        }

        if (input.length() >= formatsize)
            input = input.substring(0, len - i - formatsize);
    }

    return formattedNumberString;
}

将此函数称为..（例如）

NumberFormatterClass nfc = new NumberFormatterClass();
System.out.println(nfc.format("1032432420000000000000", 3));
System.out.println(nfc.format("1032432420000000000000", 4));
System.out.println(nfc.format("1032432420000000000000", 5));
System.out.println(nfc.format("1032432420000000000000", 2));

...问候

Android edittext：格式化数字

6 个答案: