Question

我正在尝试实现从十进制数到ascii的转换。现在，我已经硬编码为50但我稍后会使用userinput。当我运行应用程序并调用方法时，输出的内容是随机的（每次按下它都会改变）例如“[C @ 4263f600”

我在链接中跟踪了该过程：decimal to binary。为什么我会得到如此奇怪的输出？

//method
if (valid) {
     String str = ascii();
     mTextOutput.setText(str);

...

public String ascii(){
    char[] binary_reverse = new char[9];
    char[] binary = new char[9];

    int ascii = 50;
    int y = 0;

    while (ascii !=1) {
        if (ascii % 2 ==0)
        {
            binary_reverse[y]='0';
        }
        else if (ascii % 2 == 1)
        {
            binary_reverse[y]='1';
        }
        ascii /= 2;
        y++;
    }

    if (ascii ==1)
    {
        binary_reverse[y] = '1';
    }

    if (y<8) {
        for(; y < 8; y++) {
            binary_reverse[y] = '0';
        }
    }

    for (int z = 0; z < 8; z++) {
        binary[z] = binary_reverse[7-1];
    }

    String str = binary.toString();
    return str;
}

Answer 1

//你可以试试这个：

binary[z] = binary_reverse[7-1]; - So you want to set every element of binary to the value in binary_reverse[6]

//还有

 String str = binary.toString(); to String str = new String(binary);

参考：@Tim

十进制到ascii android

1 个答案: