Question

每个患者都应该有唯一的randomID，这些randomID应该按顺序排列，所以我应该这样做带回（Duplicate RandomID）和（Out of Sequence RandomID）

这是我的查询

declare @valueCheck table
(RowNumber Int Identity
,PatientID varchar(25)
,RandomID varchar(25))

insert into @ValueCheck
(PatientID, RandomID)

select
PatientID
, RandomID

From   dbo.CurrentData

where QuestionID= 200
order by patientid, RandomID

如果我应用这个条件，我会得到（不按顺序的RandomID）

Select s1.PatientID, s1. RandomID as OutOFSequence
From @ValueCheck s1
Left Join @ValueCheck s2
On s1.RandomID = s2.RandomID – 1
Where s2.RandomID is Null

如果我应用这个，我会得到（Duplicate RandomID）

select * from @ValueCheck
where RandomID in 
(Select RandomID
From @ValueCheck
Group by RandomID
Having Count(RandomID) > 1)

我想要的是，我想要一张将两种条件结合在一起的表

Answer 1

为什么不进行联合查询。

Select s1.PatientID, s1. RandomID, 'OutOFSequence'
From @ValueCheck s1
Left Join @ValueCheck s2
On s1.RandomID = s2.RandomID – 1
Where s2.RandomID is Null
union all
select PatientID, RandomID, 'Duplicate' from @ValueCheck
where RandomID in 
(Select RandomID
From @ValueCheck
Group by RandomID
Having Count(RandomID) > 1)

重复序列号和重复序列号

1 个答案: