Question

数据结构：

我\ ExampleBundle \实体\父级：

oneToMany:
    children:
        targetEntity: Children
        mappedBy    : parent
        cascade     : ["persist", "remove"]
manyToMany:
    friends:
      targetEntity  : Friend
      inversedBy    : parents
      cascade       : ["persist"]
      joinTable     :
        name        : my_parents_and_friends
        joinColumns :
            joinColum:
                name                : parent_id
                referencedColumnName: id
                onDelete            : CASCADE
        inverseJoinColumns:
            joinColum:
                name                : friend_id
                referencedColumnName: id
                onDelete            : CASCADE

。

我\ ExampleBundle \实体\儿童：

manyToOne:
    parent:
        targetEntity: Parent
        inversedBy  : children
        joinColumn  :
            name                : parent_id
            referencedColumnName: id
manyToMany:
    friends:
      targetEntity  : Friend
      inversedBy    : children
      cascade       : ["persist"]
      joinTable     :
        name        : my_children_and_friends
        joinColumns :
            joinColum:
                name                : children_id
                referencedColumnName: id
                onDelete            : CASCADE
        inverseJoinColumns:
            joinColum:
                name                : friends_id
                referencedColumnName: id
                onDelete            : CASCADE

。

我\ ExampleBundle \实体\朋友：

manyToOne:
    school:
        targetEntity: My\SchoolBundle\Entity\School
        inversedBy  : friends
        joinColumn  :
            name                : school
            referencedColumnName: id
manyToMany:
    parents:
        targetEntity: Parent
        mappedBy    : friends
    children:
        targetEntity: Children
        mappedBy    : friends

。

我\ SchoolBundle \实体\学校：

oneToMany:
    friends:
        targetEntity: My\ExampleBundle\Entity\Friend
        mappedBy    : school
        cascade     : ["persist", "remove"]

。

我\ ExampleBundle \控制器\ ParentController：

/**
 * Edit Action
 */
public function editAction(Request $request, $id)
{
    //...

    $form = $this->createForm(new ParentType($this->getUser()), $parent);

。

我\ ExampleBundle \表格\型号\ ParentType的：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    //...

    $builder->add('children', 'collection', array(
        'type' => new ChildrenType($this->user),
        'options' => array(
            'required' => true,
        ),
        'allow_add'    => true,
        'by_reference' => false,
        'allow_delete' => true,
        'prototype'    => true
    ));
}

。

我\ ExampleBundle \表格\型号\ ChildrenType：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    //...

    $builder->add('friends', 'collection', array(
        'type'    => new FriendType($this->user),
        'options' => array(
            'required' => true,
        ),
        'allow_add'    => true,
        'by_reference' => false,
        'allow_delete' => true,
        'prototype'    => true
    ));

。

我\ ExampleBundle \表格\型号\ FriendType：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    //...

    $builder->add('school', 'genemu_jqueryselect2_hidden');

ERROR:
    The form's view data is expected to be of type scalar,
    array or an instance of \ArrayAccess, but is an instance of class My\SchoolBundle\Entity\School.
    You can avoid this error by setting the "data_class" option to "My\SchoolBundle\Entity\School"
    or by adding a view transformer that transforms an instance of class My\SchoolBundle\Entity\School to scalar,
    array or an instance of \ArrayAccess.

。

然后：
我的\ ExampleBundle \表格\型号\ FriendType：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    //...

    $builder->add('school', 'genemu_jqueryselect2_hidden', array(
        'data_class' => 'My\SchoolBundle\Entity\School',
    ));

ERROR:
    ContextErrorException: Catchable Fatal Error: Object of class My\SchoolBundle\Entity\School could not be converted to string
    in /path/to/symfony2/app/cache/dev/twig/b5/df/83d3ad1c70181782da8626f8237b177e7063eb64a745f97ba87b9b8b025d.php line 323

    // View of Twig is simple like this:
    {{ form_widget(friend.school) }}

。

然后：
我没有使用GenemuFormBundle，我试图创建一个个人数据转换器。

$transformer = new SchoolTransformer($this->entityManager);
$builder->add(
    $builder->create('school',
        'hidden',
        array(
            'by_reference' => false,
            'required'     => false,
            'attr'         => array(
                'class' => 'select2'
            ),
        )
    )->addModelTransformer($transformer)
);

ERROR: This is same error above.

。

所以我认为通常的方式是实体字段，但我想为大量数据应用select2 但是，它无法生成隐藏的表单字段。

非常感谢任何帮助或想法。

Answer 1

FriendType不知道如何渲染学校实体，因此他尝试在其上调用__toString（）方法，因为她没有实现你得到这个错误。

您可以设置property_path属性以定义应呈现的字段。 http://symfony.com/doc/master/reference/forms/types/hidden.html#property-path

这样的事情可以解决你的问题：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    //...

    $builder->add('school', 'genemu_jqueryselect2_hidden', array(
        'data_class' => 'My\SchoolBundle\Entity\School',
        'property_path' => 'id'
    ));
}

隐藏字段：DataTransformer：GenemuFormBundle：Select2：Symfony2中的深层集合表单

1 个答案: