Question

您好我在这里收到超时异常，因为标题声明并且我没有找到任何相关答案，因为它是唯一发生的事务。此外，当我拿走交易状态时，我的测试通过就好了。我的创作方法：

@Transactional(readOnly = false, propagation = Propagation.REQUIRES_NEW)
public void createAMember(int memberid, String name, String address1, String address2, String town, String contact_number, int bookallowance, double balance, boolean active) {
    String SQL = "insert into member (id,name,address1,address2,town,contact_number,book_allowance, balance, active) values (?,?,?,?,?,?,?, ?, ?)";
    getJdbcTemplate().update(SQL, new Object[] { memberid,name,address1,address2,town,contact_number,bookallowance,balance,active});
    System.out.println("Created Member Name = " + name + " memberid= " + memberid);
    //throw new libException();

}

我的实际测试：

@Test
@DatabaseSetup(value="classpath:dbEntries.xml", type=DatabaseOperation.CLEAN_INSERT)
public void testCreateMember() throws SQLException{
    MemberDaoJDBCTemplate memberDaoJDBCTemplate=(MemberDaoJDBCTemplate)autoWireContext.getBean("memberDaoJDBCTemplate");
    //int firstCount=memberDaoJDBCTemplate.countAllMembers();
    memberDaoJDBCTemplate.createAMember(id,Name, Address1,Address2,Town,Contact_number,book_allowance,Balance,active);
    System.out.println("kafka");
    //int secondCount=memberDaoJDBCTemplate.countAllMembers();
    //assertNotEquals(firstCount, secondCount); 
}

我的数据源bean：

<bean id="dataSource" 
    class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
    <property name="url" value="jdbc:mysql://localhost:3306/library"/>
    <property name="username" value="root"/></bean>

我是新手，所以如果我可以添加任何东西，请说，我已经摔跤了一段时间，所以任何提示都值得赞赏。编辑1：这是我正在运行的唯一测试，即createAMember

Answer 1

似乎我要么提出了一个模糊或困难的问题，要么我以错误的方式问过它。无论如何，经过多次拔毛，我找到了这个问题的答案。我在这里尝试CreateAMember的原始代码：

public void createAMember(int memberid, String name, String address1, String address2, String town, String contact_number, int bookallowance, double balance, boolean active) { String SQL = "insert into member (id,name,address1,address2,town,contact_number,book_allowance, balance, active) values (?,?,?,?,?,?,?, ?, ?)"; getJdbcTemplate().update(SQL, new Object[] { memberid,name,address1,address2,town,contact_number,bookallowance,balance,active}); System.out.println("Created Member Name = " + name + " memberid= " + memberid); //throw new libException();

必须更整齐地构建，同时识别类型并将其整齐地放在准备好的声明中。下面的重新跳汰对我有用。 PreparedStatementCreatorFactory psc=new PreparedStatementCreatorFactory(SQL); psc.addParameter(new SqlParameter("id", Types.INTEGER)); psc.addParameter(new SqlParameter("name", Types.VARCHAR)); psc.addParameter(new SqlParameter("address1", Types.VARCHAR)); psc.addParameter(new SqlParameter("address2", Types.VARCHAR)); psc.addParameter(new SqlParameter("contact_number", Types.VARCHAR)); psc.addParameter(new SqlParameter("book_allowance", Types.INTEGER)); psc.addParameter(new SqlParameter("balance", Types.DOUBLE)); psc.addParameter(new SqlParameter("active", Types.BOOLEAN)); Object[] params=new Object[]{memberid,name, address1, address2, town, contact_number, bookallowance, balance,active}; KeyHolder holder = new GeneratedKeyHolder(); getJdbcTemplate().update(psc.newPreparedStatementCreator(params), holder); System.out.println("holder:"+holder.getKey().toString()); System.out.println("Created Record Name = " + name + " ID = " + memberid);

我原来的方法适用于纯粹的JDBC交互，这就是混乱的起因。交易需要如上所示的结构。我希望这篇文章可以帮助一个无知的人，在某些时候也像我一样。

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1 个答案: