我有Windows应用程序,我想将数据发布到Url以从Web服务获取信息 这是我使用的代码:
private string PostData(string url, string postData)
{
HttpWebRequest request = null;
if (m_type == PostTypeEnum.Post)
{
Uri uri = new Uri(url);
request = (HttpWebRequest)WebRequest.Create(uri);
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = postData.Length;
using (Stream writeStream = request.GetRequestStream())
{
UTF8Encoding encoding = new UTF8Encoding();
byte[] bytes = encoding.GetBytes(postData);
writeStream.Write(bytes, 0, bytes.Length);
}
}
else
{
Uri uri = new Uri(url + "?" + postData);
request = (HttpWebRequest)WebRequest.Create(uri);
request.Method = "GET";
}
string result = string.Empty;
using (HttpWebResponse response = (HttpWebResponse) request.GetResponse())
{
using (Stream responseStream = response.GetResponseStream())
{
using (StreamReader readStream = new StreamReader(responseStream, Encoding.UTF8))
{
result = readStream.ReadToEnd();
}
}
}
return result;
}
如何将文件添加到帖子数据?
我需要将文件发送到页面。
请问任何样品?
提前致谢,问候
答案 0 :(得分:1)
您希望将ContentType更改为“multipart / form-data”,然后HTTP请求的正文将变为一系列MIME块,每个块包含您传递的数据的不同元素。
以下是formatting the multipart/form-data的W3C规范。