innerHTML替换上的错误分配

Question

我以前从来没有做过任何关于Javascript的事情，在尝试用tampermonkey制作一个chrome用户脚本之后我似乎无法通过这个动作......这个功能运行得很好，但是我一直得到一个糟糕的任务或没有错误，但行动不会通过......这可能看起来非常丑陋或糟糕，但任何关于如何根据文本是否为25-1

感谢任何可以提供帮助的人。

function W01() 
{       
if (/another 25 seconds before attempting to search again/i.test (document.body.innerHTML) )
{
    document.body.innerHTML() = document.body.innerHTML.replace('Sorry, but you can only perform one search every 25 seconds. Please wait another 25 seconds before attempting to search again.', 'Press F5 or Reload the page now');
}
else if (/another 24 seconds before attempting to search again/i.test (document.body.innerHTML) )
{
    document.body.innerHTML() = document.body.innerHTML.replace('Sorry, but you can only perform one search every 25 seconds. Please wait another 24 seconds before attempting to search again.', 'Press F5 or Reload the page now');
}
    else if (/another 23 seconds before attempting to search again/i.test (document.body.innerHTML) )
    {
        document.body.innerHTML() = document.body.innerHTML.replace('Sorry, but you can only perform one search every 25 seconds. Please wait another 23 seconds before attempting to search again.', 'Press F5 or Reload the page now');
    }
}

Answer 1

删除()中的innerHTML()。

应该是：

document.body.innerHTML = "some HTML";

请注意，它不是一个功能。这是一个属性。

例如，这样做：

document.body.innerHTML = document.body.innerHTML.replace('Sorry, but you can only perform one search every 25 seconds. Please wait another 23 seconds before attempting to search again.', 'Press F5 or Reload the page now');