我正在编写一个程序来划分有理数,但我希望它能够处理分数。我想将1除以1/3但我的程序在处理整数时遇到错误。我试图将整数转换为合理的几种不同的方式,但没有任何作用。任何帮助或指导将不胜感激。
这里我一直收到的错误是来自代码底部的断言语句的标志。
追踪(最近一次通话): 文件" E:\ Python \ Rational号码扩展名excercise.py",第47行,in 断言Rational(3)== 1 / r3,"除法测试失败。" TypeError:/:' int'不支持的操作数类型和' Rational'
class Rational(object):
""" Rational with numerator and denominator. Denominator
parameter defaults to 1"""
def __init__(self,numer,denom=1):
#test print('in constructor')
self.numer = numer
self.denom = denom
def __truediv__(self,param):
'''divide two rationals'''
#test print('in truediv')
if type(param) == int: # convert ints to Rationals
param = Rational(param)
if type(param) == Rational:
# find a common denominator (lcm)
the_lcm = lcm(self.denom, param.numer)
# adjust the param value
lcm_numer = (the_lcm * param.numer)
lcm_denom = (the_lcm * param.denom)
true_param = int(lcm_denom / lcm_numer)
#print(int(lcm_denom / lcm_numer))
# multiply each by the lcm, then multiply
numerator_sum = (the_lcm * self.numer/self.denom) * (true_param)
#print(numerator_sum)
#print(Rational(int(numerator_sum),the_lcm))
return Rational(int(numerator_sum),the_lcm)
else:
print('wrong type') # problem: some type we cannot handle
raise(TypeError)
def __rdiv__(self,param):
'''divide two reversed rationals'''
# mapping is correct: if "(1) / (x/x)", 1 maps (to 1/1)
if type(self) == int:
self.numer = self
self.denom = 1
return self.__truediv__(self.numer)
return self.__truediv__(self.denom)
r1 = Rational(2,3)
r2 = Rational(1,4)
r3 = Rational(1,3)
assert Rational(2) == r1 / r3, "Division test failed."
assert Rational(3) == 1 / r3, "Division test failed."
答案 0 :(得分:2)
def __rdiv__(self,param):
'''divide two reversed rationals'''
# mapping is correct: if "(1) / (x/x)", 1 maps (to 1/1)
if type(self) == int:
self.numer = self
self.denom = 1
type(self) == int
永远不会评估为True:如果您在__rdiv__
上运行Racional
,则自我将始终为Racional
。您将要测试param
,而不是分区的左侧(在您的示例中为1)。