Question

我是PHP的新手，想要创建一个表单，用户将数据插入表单（可以正常工作），然后存储在MYSQL DB上（可以正常工作），现在必须显示数据，然后必须是能够修改某些记录，现在我有记录显示的部分以及＆＃34;编辑＆＃34;按钮，但是因为同一条记录不断出现，某些地方出了问题，所以我想我的代码有问题:(

请帮助：

这是index.php代码：

<?php
include('dbinfo.php');
$sql="SELECT * FROM stats";

$result = mysql_query($sql, $db) or die (mysql_error()); 
$pageTitle = "My Stats Database";
include("header.php");

print <<<HERE
<h2> My Contacts</h2>
Select a Record to update <a href="addstat.php"> add new stat</a>.
<table id="home">
HERE;

while ($row=mysql_fetch_array($result)){
    $id=$row["id"];
    $type=$row["type"];
    $depthead=$row["depthead"];
    $person=$row["person"];
    $descr=$row["descr"];
    $recdate=$row["recdate"];
    $tolog=$row["tolog"];
    $senttorev=$row["senttorev"];
    $recfromrev=$row["recfromrev"];

print <<<HERE
<tr>
<td>
<form method="POST" action="updateform.php">
<input type="hidden" name="sel_record" value="$id">
<input type="submit" name="update" value="   Edit   " </form>
</td>

<td><strong> Description: </strong>$descr,<p> <strong>Type: </strong>$type</p> <p><strong> Department Head: </strong>$depthead</p> 
<strong> Test Analyst: </strong> $person<br/></td>
HERE;
}
print "</tr></table></body></html>";


?>

然后这是我的update updateform.php脚本：

<?php
include("dbinfo.php");
$sel_record = $_POST['sel_record'];
//$sel_record = (isset($_POST['sel_record'])) ? $_POST['sel_record'] : ''; 

$sql = "SELECT * FROM stats WHERE id = 'sel_record'";

//execute sql query  and get result
$result = mysql_query($sql, $db) or die (mysql_error());
if (!$result) {
    print "<h1> Something went wrong!</h1>";
} else

{ //begin while loop

    while ($record = mysql_fetch_array($result, MYSQL_ASSOC)){
    $id = $record["id"];
    $type = $record['type'];
    $depthead = $record['depthead'];
    $person = $record["person"];
    $descr = $record["descr"];
    $recdate = $record["recdate"];
    $tolog = $record["tolog"];
    $senttorev = $record["senttorev"];
    $recfromrev = $record["recfromrev"];
}
    }

  //end while loop


$pagetitle = "Edit Stat";
include ("header.php");

print <<<HERE

    <h2> Modify this Stat</h2>
    <p> Change the values in the boxes and click "Modify Record" button </p>

    <form id="stat" method="POST" action="update.php">
    <input type="hidden" name="id" value="$id">
<div>
     <label for="type">Type*:</label>
     <input type="text" name="type" id="type" value="$type">
</div>
<p>
</p>
<div>
        <label for = "depthead" >Department Head*:</label>
    <input type = "text" name = "depthead" id = "depthead" value = "$depthead">
</div>
<p>
</p>
<div>
    <label for="person">Test Analyst*:</label>
    <input type="text" name="person" id="person" value="$person">
</div>
<p>
</p>
<div>
    <label for="descr">Description*:</label>
    <input type="text" name="descr" id="descr" value="$descr">
</div>
<p>
</p>

<div>
    <label for="recdate">Date Received*:</label>
    <input type="text" name="recdate" id="recdate" value="$recdate">
</div>
<p>
</p>
<div>
    <label for="tolog">Date to log*:</label>
    <input type="text" name="tolog" id="tolog" value="$tolog">
</div>
<p>
</p>
<div>
    <label for="senttorev">Sent to Rev:</label>
    <input type="text" name="senttorev" id="senttorev" value="$senttorev">
</div>
<p>
</p>
<div>
    <label for="recfromrev">Received from Rev*:</label>
    <input type="text" name="recfromrev" id="recfromrev" value="$recfromrev">
</div>
<p>
</p> 
<div id="mySubmit">
<input type="submit" name="submit" value="Modify Record">
</div>
</form>
HERE;

?>

然后mysql的实际更新有一个update.php脚本：

<?php

include "dbinfo.php";

    $id = $_POST['id'];
    $type = $_POST['type'];
    $depthead = $_POST['depthead'];
    $person = $_POST['person'];
    $descr=$_POST['descr'];
    $recdate=$_POST['recdate'];
    $tolog=$_POST['tolog'];
    $senttorev=$_POST['senttorev'];
    $recfromrev=$_POST['recfromrev'];

    $sql="UPDATE stats SET

            depthead='$depthead',
            person='$person',
            descr='$descr',
            recdate='$recdate',
            tolog='$tolog',
            senttorev='$senttorev',
            recfromrev='$recfromrev'
        WHERE id='$id'";

    $result=mysql_query($sql) or die (mysql_error());

    print "<html><head><title>Update Results</titlel></head><body>";
    include "header.php";
    print <<<HERE
    <h1>The new Record looks like this: </h1>

    <td>
    <p><strong>Type: </strong>$type</p> 
    <p><strong>Department Head: </strong>$depthead</p> 
    <p><strong>Test Analyst: </strong> $person</p>
    <p><strong>Description: </strong>$descr</p>  
    <p><strong>Received Date:</strong>$recdate</p>
    <p><strong>Date to Log:</strong>$tolog</p>
    <p><strong>Sent to rev:</strong>$senttorev</p>
    <p><strong>Received from Rev:</strong>$recfromrev</p>
    <br/>
HERE;

有人可以告诉我为什么只有一个记录一直出现并不重要我从index.php页面中选择哪一个。出于某种原因，我认为这是我的$sel_record变量，但我不确定并且已经用完了...

提前谢谢..

Answer 1

这是您在updateform.php中的问题：

$sql = "SELECT * FROM stats WHERE id = 'sel_record'";

应该是：

$sql = "SELECT * FROM stats WHERE id = $sel_record";

您错过了$符号来调用变量，并且您不需要在ID周围使用引号。

使用MYSQL数据更新表单

1 个答案: