Question

我尝试在 SELECT 语句中使用表类型的变量，但它发生错误：

DECLARE
    TYPE v2t IS TABLE OF table_a.id%TYPE INDEX BY BINARY_INTEGER;
    TYPE test_type IS TABLE OF table_a.id%TYPE INDEX BY BINARY_INTEGER;
    test_table1 test_type;
    test_table2 test_type;
    databaseArray v2t;
BEGIN
    SELECT id BULK COLLECT INTO test_table1 FROM 
        (SELECT id FROM test_a WHERE some_flag = 1);
    FOR i IN 1..test_table1.COUNT LOOP
        databaseArray(i) := test_table1(i);
    END LOOP;

    SELECT id BULK COLLECT INTO test_table2 FROM 
           (SELECT id FROM TABLE(databaseArray));  --error ORA-22905
END;

test_table1 在表格中不可见。有没有办法在SELECT语句中使用 test_table1 ？我需要有两个结果子集。

Answer 1

如果您不想在架构级别声明自己的类型，可以使用built-in table type，只要有一个与您的基础数据类型匹配且您没有太多的值放进去：

DECLARE
  TYPE test_type IS TABLE OF user_objects.object_id%TYPE
    INDEX BY BINARY_INTEGER;
  test_table1 test_type;
  test_table2 test_type;
  databaseArray sys.odcinumberlist;
BEGIN
  SELECT object_id
  BULK COLLECT INTO test_table1
  FROM user_objects;

  databaseArray := sys.odcinumberlist();
  FOR i IN 1..test_table1.COUNT LOOP
    databaseArray.extend;
    databaseArray(i) := test_table1(i);
  END LOOP;

  SELECT column_value
  BULK COLLECT INTO test_table2
  FROM TABLE(databaseArray);
END;
/

anonymous block completed

在SELECT语句中使用表类型

1 个答案: