Question

main.cpp：

Simple2DMatrix＆amp; Simple2DMatrix :: assign（const Simple2DMatrix＆amp; matrixB） {

if ((numRows == matrixB.numRows)
    && (numCols == matrixB.numCols)
    )
{

    for (int r = 0; r < numRows; r++)
    {
        for (int c = 0; c < numCols; c++)
        {
            this->setElement(r, c, matrixB.getElement(r, c));
        }
    }
    return (*this);
}
else

{
    throw "Dimensions does not match!";
}

}

并添加为：

  if ((this->numRows == matrixB.numRows)
    && (this->numCols == matrixB.numCols)
    )
{

    for (int r = 0; r < this->numRows; r++)
    {
        for (int c = 0; c < this->numCols; c++)
        {
            this->setElement(r, c, this->getElement(r, c) + matrixB.getElement(r, c));
        }
    }
    return (*this);
}
else

{
    throw " Dimensions does not match!";
}

因此，任务将是： {

if ((numRows == matrixB.numRows)
    && (numCols == matrixB.numCols)
    )
{

    for (int r = 0; r < numRows; r++)
    {
        for (int c = 0; c < numCols; c++)
        {
            this->setElement(r, c, matrixB.getElement(r, c));
        }
    }
    return (*this);
}
else

{
    throw "Dimensions does not match!";
}

}

并在operator +的标题中：

    Simple2DMatrix<T> matrixTemp(matrixA.numRows, matrixA.numCols);

    matrixTemp.sum(matrixA, matrixB);
    return (matrixTemp);

并且对于operator =：

this->assign(matrixB);
return(*this);

非常感谢你的所有信息。

Answer 1

这是你的代码（operator +）：

if ((this->numRows == matrixB.numRows)
    && (this->numCols == matrixB.numCols)
    )
{

    for (int r = 0; r < matrixA.numRows; r++)
    {
        for (int c = 0; c < matrixA.numCols; c++)
        {
            this->setElement(r, c, matrixA.getElement(r, c) + matrixB.getElement(r, c));
        } //what is matrixA?
    }
    return (*this); //what you want to return?? it seems you are doing B=B+C
}
else

{
    throw " Dimensions does not match!";
}

实际上你需要先创建一个类的临时对象并存储添加的内容 B和C在里面。然后返回那个临时变量。

重载赋值运算符不适用于链接c ++

1 个答案: