使用 FHStwitterEngine 发布图片时返回错误但如果我发布的推文没有成功发布
-(void)postTweet:(NSString*)message withImage:(UIImage*)img {
dispatch_async(GCDBackgroundThread, ^{
@autoreleasepool {
NSString *strMsg =[NSString stringWithFormat:@"%@",message];
NSData *imgData =UIImagePNGRepresentation(img);
[UIApplication sharedApplication].networkActivityIndicatorVisible = YES;
NSError *returnCode = [[FHSTwitterEngine sharedEngine]postTweet:strMsg withImageData:imgData];
[UIApplication sharedApplication].networkActivityIndicatorVisible = NO;
NSString *title = nil;
NSString *message = nil;
if (returnCode) {
title = [NSString stringWithFormat:@"Error %d",returnCode.code];
message = returnCode.localizedDescription;
} else {
title = @"Tweet Posted";
message = message;
}
dispatch_sync(GCDMainThread, ^{
@autoreleasepool {
UIAlertView *av = [[UIAlertView alloc]initWithTitle:title message:message delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[av show];
}
});
}
});
}
- (IBAction)btnPost:(id)sender {
NSString *str =@"Test5";
UIImage *image =[UIImage imageNamed:@"contact.png"];
if (image ==nil) {
[self postTweet:str];
}else {
[self postTweet:str withImage:image];
}
}
答案 0 :(得分:0)
当前版本的FHSTwitterEngine和发布图片存在问题。我在我的应用程序中遇到了同样的问题,但是能够使用此分叉版本的更新来解决它:
https://github.com/alvani/FHSTwitterEngine/blob/master/FHSTwitterEngine/FHSTwitterEngine.m
最简单的方法是将其复制/粘贴到FHSTwitterEngine.m中,但这是您需要的具体更改:
1599号线或附近:
- (NSError *)sendPOSTRequestForURL:(NSURL *)url andParams:(NSDictionary *)params
...
[body appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"%@\"\r\n",key] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[@"\r\n" dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:data];
在下面添加以下代码:
if ([obj isKindOfClass:[NSData class]]) {
[body appendData:[@"\r\n" dataUsingEncoding:NSUTF8StringEncoding]];
}
在688线或附近:
- (NSError *)postTweet:(NSString *)tweetString withImageData:(NSData *)theData inReplyTo:(NSString *)irt {
...
NSMutableDictionary *params = [NSMutableDictionary dictionary];
params[@"media[]"] = theData;
在下面添加以下代码:
params[@"status"] = tweetString;
希望这有帮助!