Question

我正在编写一个程序来实现后缀计算器，它给了我完全错误的答案。真的很感激帮助

class stacks {
public:
  typedef int List;
  static const int size = 100;

  stacks() {
    use = 0;
  }

  void push(List entry) {
    data[use] = entry;
    ++use;
  }
  List pop() {
    if(!empty()) {
      --use;
      return data[use];
    }
  }

  bool empty() const {
    return use == 0;
  }
  int Size() const {
    return use;
  }

private:
  List data[size];
  int use;

};

int main() {

  stacks s;
  string input;

  int final;

  ifstream infile("foo.txt",ios::in);

  while (getline(infile, input))
    cout << "Expression: ";
  for (int i = 0; i<input.length(); i++) {

    cout << input[i];
    auto oper1 = s.pop();
    auto oper2 = s.pop();

    if(input[i] == '1' || input[i] == '2' || input[i] == '3' || input[i] == '4' ||     nput[i] == '5' || input[i] == '6' || input[i] == '7' || input[i] == '8' || input[i] == '9')
      s.push(input[i] - '0');

    if(input[i] == '+')
      s.push(oper1 + oper2);
    if(input[i] == '-')
      s.push(oper1 - oper2);
    if(input[i] == '*')
      s.push(oper1 * oper2);
    if(input[i] == '/')
      s.push(oper1 / oper2);

  }
  final = s.pop();
  cout << endl << "Value = " << final << "." << endl << endl;

}

你推荐什么？感谢

Answer 1

您需要等到pop()，直到您知道有运营商为止。当你不应该这样做的时候，你就会从堆栈中弹出东西。

修复后计算器，返回错误的值

1 个答案: