JAXB：unmarshalexception - 带有链接异常：[java.io.IOException：Stream closed]

Question

我正在尝试使用SAX解析我的xml，我想使用JaxB来构建我的地图我的元素名称及其值。我也想覆盖startElement和endElemnt但是我到达这里直到目前为止我正在解组例外。非常感谢！

JAXBContext jaxbContext = JAXBContext.newInstance（my.class）;

      Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();  


     UnmarshallerHandler unmarshallerHandler = jaxbUnmarshaller.getUnmarshallerHandler();

     SAXParserFactory spf = SAXParserFactory.newInstance();
     SAXParser sp = spf.newSAXParser();
     XMLReader xr = sp.getXMLReader();
     xr.setContentHandler(unmarshallerHandler);


     InputStream inputStream =   this.getClass().getResourceAsStream("my.xml");
     InputSource inputSource = new InputSource(inputStream);

     xr.parse(inputSource);



      JAXBElement  element  = (JAXBElement) jaxbUnmarshaller.unmarshal(inputSource);


       //or if I unmarahall to specific class object still i get same exception.

    } catch (JAXBException e) {  
     // some exception occured  
       e.printStackTrace();  
    }

Answer 1

在对其使用SAX解析后，您无法解散InputSource。要在getResult上获取对象UnmarshallerHandler。