MySQL查询与匹配和总结 - 联盟表

Question

我有5张桌子：

• 玩家（id，name，team_id）
• 团队（身份证，姓名）
• 结果（id，game_id，player.id，位置）
• 游戏（身份证，地点）
• 得分（位置，得分）

为follows

我想制作像this

这样的联赛表

我很困惑如何总结每位球员的得分。到目前为止，这是我的代码：

SELECT Players.name, Teams.name, Results.position FROM Players
INNER JOIN Teams ON Players.team_id = Teams.id
JOIN Results ON Player.id = Results.player_id
JOIN Scores ON Results.position = Scores.scores

有什么想法吗？

Answer 1

SELECT Players.name, 
       Teams.name,
       sum(Results.position * Scores.scores) as scores
FROM Players
JOIN Teams ON Players.team_id = Teams.id
JOIN Results ON Player.id = Results.player_id
JOIN Scores ON Results.position = Scores.scores
GROUP BY Players.name, Teams.name

Answer 2

要列出所有玩家（无论他们是否出现在结果表中），您必须使用LEFT JOIN。

SELECT p.name player_name,t.name team_name,SUM(COALESCE(s.score,0)) as total_score
FROM players p
INNER JOIN teams t ON t.id = p.team_id
LEFT JOIN results r ON p.id = r.player_id
LEFT JOIN scores s ON s.position = r.position
GROUP BY p.id
ORDER BY total_score desc