我在Flask-Admin中面临性能问题,尽管Flask应用程序的性能很好。
我的模特是:
class Ck(Base):
__tablename__ = "ck"
id = Column(Integer, primary_key=True, autoincrement=True)
nazev = Column(String(100))
kontakt = Column(Text)
terms = relationship(Term, backref=backref('ck', lazy='noload'), lazy='dynamic')
class Term(Base):
__tablename__ = "term"
id = Column(Integer, primary_key=True, autoincrement=True)
hotel_id = Column(Integer, ForeignKey('hotel.id'))
ck_id = Column(Integer, ForeignKey('ck.id'))
...
addons = relationship(Addon, secondary=term_addon, backref=backref('term', lazy='noload'), lazy='dynamic')
class Hotel(Base):
__tablename__ = "hotel"
id = Column(Integer, primary_key=True, autoincrement=True)
country_id = Column(Integer, ForeignKey('country.id'))
area_id = Column(Integer, ForeignKey('area.id'))
...
photos = relationship(Photo, backref=backref('hotel', lazy='select'), lazy='dynamic')
terms = relationship(Term, backref=backref('hotel', lazy='noload'), lazy='dynamic')
class Addon(Base):
__tablename__ = "addon"
id = Column(Integer, primary_key=True, autoincrement=True)
...
在插件中有很多记录和更多内容。如果我点击任意位置以获取Flask-Admin中的Hotel,Term,Ck或Addon的详细信息,则无法进行,因为它在超时之前无法完成。
请你告诉我哪里可以改进它? 谢谢
答案 0 :(得分:3)