Question

我试图根据数组的一个属性在ruby中排序大约20个哈希值。我想只返回前三个哈希键，但我不想比较每一个。

下面是一个类似于我尝试排序的示例。我想根据powerrank进行排序。

["green", {:price=>24.88, :numreviews=>822, :avgStarsRank=>41.0, :reviewsrank=>28, :powerrank=>73.976}]

["steve", {:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>42.992000000000004}]

["joey", {:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>80.054}]

["board", {:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>47}]

["john", {:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>16}]

为此，我想要的所有内容都是[＆＃34; joey＆＃34;，＆＃34; green＆＃34;，＆＃34; board＆＃34;]。关于如何解决这个问题的任何建议？

编辑：以下是原始哈希表单中的示例：

powerrankings =
    {
        "green"=>{:price=>24.88, :numreviews=>822, :avgStarsRank=>41.0, :reviewsrank=>28, :powerrank=>73.976}, 
        "steve"=>{:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>42.992000000000004}, 
        "joey"=>{:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>80.054}}
        "board"=>{:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>47}, 
        "john"=>{:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>16}
    }

Answer 1

假设powerrankings不是你所展示的，而是

powerrankings = {
  "green" => {:price=>24.88, :numreviews=>822, :avgStarsRank=>41.0, :reviewsrank=>28, :powerrank=>73.976}, 
  "steve" => {:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>42.992000000000004}, 
  "joey" => {:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>80.054},
  "board" => {:price=>14.96, :numreviews=>3, :avgStarsRank=>40.0, :reviewsrank=>0, :powerrank=>47}, 
  "john" => {:price=>40.27, :numreviews=>814, :avgStarsRank=>44.0, :reviewsrank=>28, :powerrank=>16}
}

然后，

powerrankings.sort_by{|_, h| h[:powerrank]}.reverse.first(3).map(&:first)
# => ["joey", "green", "board"]

在ruby中对哈希进行排序的最有效方法是什么？

1 个答案: