我正在开发一个需要解析一些网页的项目,为此我正在使用Beautifulsoup。我能够获取信息,但字符串中有许多Unicode,换行符,制表符空格字符和额外空格。我试图使用正则表达式来删除这些东西。我写的脚本在一个字符串上运行正常,我在一个简单的脚本中声明但它不适用于真实的东西。
我的代码:
str = '\xa9 Copyright 2009-10 \n\t\t\t\t All Rights Reserved. (Best viewed in 1024x768 \n\t\t\t\tresolution & IE 6.0) break\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0 \nChief Engineer'
reSpace = re.compile(' +')
reUni = re.compile( '(\\xa9|\\n|\\t|\\xa0)')
str = reSpace.sub(' ', str)
str = reUni.sub('', str)
print str
感谢您的回复。 我的真实代码是:
import re
from bs4 import BeautifulSoup
import os
tagslist = [] # keeps track of the tags that have been encountered
filehandle = {} # stores the file handles for every rag
reUni = re.compile( '((\\xa9)|(\\n)|(\\t)|(\\xa0))')
reSpace = re.compile(' +')
page = "filename.html" # html file which needs to be parsed
fread = open(page, 'r')
soup = BeautifulSoup(fread.read())
fread.close()
if re.match( r'.*\.htm$', page): # removes the .html or htm to remove "." to be enable to create a folder named "filename"
page = site+"_parsed/"+page[:-4]+"_data"
else:
page = site+"_parsed/"+page[:-5]+"_data"
if not os.path.exists(page): #creates the folder named "filename"
os.makedirs(page)
for tag in soup.find_all():
if tag.string: #if the tag encountered has a child string or not
#if tag is encountered for the first time than create the file to hold its strins and declare the file handle for it
if tag.name not in tagslist:
tagStrFile = page+ "/" + tag.name +"_str.txt"
filehandle[tag.name] = "handle_" + tag.name
vars()[filehandle[tag.name]] = open(tagStrFile, 'w+') #declare the file handle
tagslist.append(tag.name)
filehandle[tag.name] = vars()[filehandle[tag.name]]
str = (repr(tag.string))
str = str[2:-1]
str = reUni.sub('', str)
str = reSpace.sub(' ', str)
if str == '':
continue
filehandle[tag.name].write(str)
filehandle[tag.name].write("\n")
for tag in tagslist: #close all the files
filehandle[tag].close()
它创建的一小部分数据:
INTRODUCTION
SETUP
\xa0STRUCTURE \n OF THE ORGANISATION
The Category wise position as on 31-03-2012 of the Sanctioned Strength \n and the Vacant Posts.
Sr.No.
Name \n of the Post/Designation
Sanctioned \n Strength
感谢
答案 0 :(得分:2)
要将多个空格(包括不间断空格)折叠为一个,您只需要一个正则表达式:
re.sub(ur'[\s\xa0]+', u' ', samplestr)
演示:
>>> import re
>>> samplestr = u'\xa9 Copyright 2009-10 \n\t\t\t\t All Rights Reserved. (Best viewed in 1024x768 \n\t\t\t\tresolution & IE 6.0) break\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0\xa0 \nChief Engineer'
>>> re.sub(ur'[\s\xa0]+', u' ', samplestr)
u'\xa9 Copyright 2009-10 All Rights Reserved. (Best viewed in 1024x768 resolution & IE 6.0) break Chief Engineer'