Question

我想要总结我的总和函数，请帮助我，谢谢这是我的问题：

SELECT t1.province, t2.fullname,sum(t1.total_vote) AS total
FROM votes AS t1, candidate AS t2
WHERE t1.candidate_id = t2.id
GROUP BY t2.id, t1.province
ORDER BY t2.id

Answer 1

所以只需使用concat即可。（并且inner join会更整洁。）

SELECT concat(t2.fullname, ' has ', sum(t1.total_vote), ' votes in ', t1.province, '.') AS concatinated_line
FROM votes AS t1
INNER JOIN candidate AS t2 ON t1.candidate_id = t2.id
GROUP BY t2.id, t1.province
ORDER BY t2.id

Answer 2

上面的答案应该是正确的，只需在SELECT：

中添加一个结束的parens

SELECT concat(t2.fullname, ' has ', sum(t1.total_vote), ' votes in ', t1.province, '.') AS concatinated_line
FROM votes AS t1
INNER JOIN candidate AS t2 ON t1.candidate_id = t2.id
GROUP BY t2.id, t1.province
ORDER BY t2.id

Answer 3

试试这个：

   SELECT fullname , GROUP_CONCAT(cast(total as char))
FROM
(
     SELECT t2.fullname fullname,sum(t1.total_vote) AS total
     FROM votes AS t1, candidate AS t2
     WHERE t1.candidate_id = t2.id
     GROUP BY t2.id, t1.province
     ORDER BY t2.id
) s

带sum函数的GROUP_CONCAT

3 个答案: