Question

我正在编写一个需要将用户输入读入字符串对象的程序。我使用了getline（cin，name），但是当它到达提示符时，我可以输入任何内容并按Enter键，但它只是转到下一行，光标将一直闪烁，提示获得更多输入。从本质上讲，输入的提示似乎永远不会结束，无论我输入多少个字符或输入多少次。我甚至不知道它是否真的将输入发送到字符串对象中。可能导致这种情况的原因是什么？

这是迄今为止的主要功能的全部内容（它不完整，switch-case最终将有6个选项，但它编译时没有错误）相关部分从switch case 1开始：

#include <string>
#include <array>
#include <iostream>
#include "stdlib.h"
#include "Bank.h"   //My own class. There is also a Bank.cpp, but I won't include the code in these unless they're deemed relevant

using namespace std;

void displayAccountInfo(); //will retrieve info on bank object

void main()
{
   int accsCreated = 0; //Keeps track of how many accounts have been created so far. Allows placement of pointer to new bank object at an empty array index.
   int option = 0;      //Stores the option chosen by the user. Used in switch-case. Also ends do-while loop when ==6.
   Bank* accounts[10];  //Will hold pointers to each bank object created by user in sequential order. No more than 10 accounts will ever be created.
   Bank* accpntr;       //Will point to one of the Bank objects. Used to initialize a pointer to the object in the accounts[] array.

   //begin Menu prompt
   do
   {
      cout << "[1] Create Bank object with values for accountNumber, name, and balance." << endl;
      cout << "[2] Create Bank object with no parameters." << endl;
      cout << "[6] End program" << endl;
      cin >> option;

      //begin option branch:
      switch (option)
      {
      case 1:
         {
            int num;             //holds account number
            string name;         //will hold account name as string object for use in Bank constructor
            double balance;      //holds account balance

            cout << endl << "Enter an account number: ";
               cin >> num;
            cout << endl << "Enter a name for the account: ";
               cin.ignore(std::numeric_limits<std::streamsize>::max()); //clears cin's buffer so getline() does not get skipped
               getline(cin,name);
            cout << endl << "Enter the balance of the account: ";
               cin >> balance;
            cout << endl;

            accpntr = new Bank(num, name, balance);   //creates a new bank object with attributes and a reference to it
            accounts[accsCreated] = accpntr; //adds pointer to new bank object to first empty spot in array
            accsCreated++;   //increments total of how many bank objects have been created/what index position of accounts[] to create the next one at
         }  break;   //end case 1
      case 2:
         {
            accpntr = new Bank();   //creates a new bank object with an accountNumber of 9999, an empty name attribute, and a balance value of zero.
            accounts[accsCreated] = accpntr; //adds pointer to new bank object to first empty spot in array
            accsCreated++;   //increments total of how many bank objects have been created/what index position of accounts[] to create the next one at
         }  break;   //end case 2

      case 6:
         {
            cout << "Ending Program." << endl;
         }
      }  //end switch-case block
   }
   while (option != 6); //end menu prompt when user chooses option 6.
      //end menu block
}  //end function main()

Answer 1

使用交替的提示和输入，这会在输入中包含线条结构，您应该坚持使用面向行的输入并将所有内容作为一行读取，并使用在适当的时候从字符串转换数值的操作。

这应该比使用行分隔符更加强大。

getline（cin，name）导致看似永无止境的输入提示

1 个答案: