malloc.c:2451:sYSMALLOc:断言...失败

时间:2014-04-06 02:05:43

标签: c++ vector heap-corruption

我不能为我的生活找出正在发生的事情。这是我得到的错误:

alloc static vecs
a.out: malloc.c:2451: sYSMALLOc: Assertion `(old_top == (((mbinptr) (((char *) &((av)->bins[((1) - 1) * 2])) - __builtin_offsetof (struct malloc_chunk, fd)))) && old_size == 0) || ((unsigned long) (old_size) >= (unsigned long)((((__builtin_offsetof (struct malloc_chunk, fd_nextsize))+((2 * (sizeof(size_t))) - 1)) & ~((2 * (sizeof(size_t))) - 1))) && ((old_top)->size & 0x1) && ((unsigned long)old_end & pagemask) == 0)' failed. Aborted (core dumped)

错误发生在类Halton中的函数qmc中,我在其中包含了相关位。正如您所看到的,第一个print语句&#34; alloc static vecs&#34;执行,但语句std::vector<double> H(s);似乎没有,因为紧跟在它之后的print语句不会执行。

现在,我应该提一下,当我用static std::vector<int> bases = FirstPrimes(s);替换Halton中的语句static std::vector<int> bases = {2,3,5,7,11,13};时(RHS是FirstPrimes()的返回数组,只是硬编码)然后那里没错。

Halton中有更多功能(它会返回std::vector),但为了简洁,我省略了它们。如果有人想尝试自己运行它,我会添加它们,只需要问一下!

我使用的是g ++ 4.6和Ubuntu 12.04,编译命令是g++ -std=c++0x scratch.cpp QMC.cpp

main(scratch.cpp):

#include <iostream>
#include <vector>
#include "QMC.h"

int main() {
  QMC qmc;

  std::vector<double> halton = qmc.Halton(6,1);
}

QMC.h:

#ifndef QMC_H
#define QMC_H

#include <iostream>
#include <cmath>                                 
#include <vector>

class QMC {
 public:
  QMC();
  bool isPrime(int n);
  std::vector<int> ChangeBase(int n, int radix);
  std::vector<int> NextChangeBase(std::vector<int>& a_in, int radix);
  double RadicalInverse(std::vector<int>& a, int b);
  std::vector<int> FirstPrimes(int n);
  std::vector<double> Halton(int s, int n = 0);
};
#endif

QMC.cpp:

#include "QMC.h"

QMC::QMC(){}

std::vector<double> QMC::Halton(int s, int n) {
  static std::vector<std::vector<int> > newBases(s);
  static std::vector<int> bases = FirstPrimes(s);

  /* replacing the statement immediately above with 
     static std::vector<int> bases = {2,3,5,7,11,13}; fixes it */

  std::cout << "alloc static vecs \n";

  std::vector<double> H(s);

  std::cout << "alloc H \n";

  // ...there's more to this function, but the error occurs just above this.
}

std::vector<int> QMC::FirstPrimes(int n) {

  std::vector<int> primes(n);
  primes[0] = 2;

  int testNum = 3;

  for (int countOfPrimes = 1; countOfPrimes <= n; ++countOfPrimes) {
    while (isPrime(testNum) == false)
      testNum = testNum + 2;

    primes[countOfPrimes] = testNum;
    testNum = testNum + 2;
   }

  return primes;
}

bool QMC::isPrime(int n) {
  if (n == 1) return false;  // 1 is not prime                                                                                                   
  else if (n < 4) return true;  // 2 & 3 are prime                                                                                               
  else if (n % 2 == 0) return false; // even numbers are not prime                                                                               
  else if (n < 9) return true; // 5 & 7 are prime                                                                                                
  else if (n % 3 == 0) return false;  // multiples of 3 (> 3) are not prime                                                                      
  else
    {
      int r = floor(sqrt((double)n));
      int f = 5;

      while (f <= r)
        {
          if (n % f == 0) return false;
          if (n % (f + 2) == 0) return false;
          f += 6;
        }

      return true;
    }
}

1 个答案:

答案 0 :(得分:2)

FirstPrimes有缓冲区溢出。相关部分:

std::vector<int> primes(n);
primes[0] = 2;

for (int countOfPrimes = 1; countOfPrimes <= n; ++countOfPrimes)
   primes[countOfPrimes] = testNum;

对于大小为n的向量,valud索引为0n-1。在最后一次循环迭代中,您将进行越界访问。

我建议将[ ]更改为.at( ),以及修复逻辑错误。如果您碰巧使用n == 0调用此函数,这也可以防止出现问题。