编辑：我解决了。问题是我试图在错误的位置清除扫描仪中保存的先前值（需要在if语句之外）。我还使用switch变量清理了continueInput方法。我会将正确的版本作为答案发布。
我试图用循环创建对象，然后将它们存储在我以后打印到文件的arraylist中。我可以很好地创建第一个对象，但是在循环的第二次迭代中，我无法移动进入卡通名称。我得到了这个名字的提示，但无论我输入什么，都没有任何反应。
这是我的主要课程：
import java.util.ArrayList;
import java.util.InputMismatchException;
import java.util.Scanner;
enum CartoonType{FOX,CHICKEN,RABBIT,MOUSE,DOG,CAT,BIRD,FISH,DUCK,RAT,NULL};
public class Main {
public static void main(String[] args) {
Scanner stdin = new Scanner(System.in);
ArrayList<CartoonStar> cartoonStars = new ArrayList<CartoonStar>();
String cartoonName;
CartoonType cartoonType;
String cartoonTypeString;
int popularityIndex;
boolean moreInput;
int counter = 0;
do {
cartoonName = cartoonName(stdin);
cartoonType = cartoonType(stdin);
cartoonTypeString = cartoonType.toString();
popularityIndex = popularityNumber(stdin);
cartoonStars.add(new CartoonStar(cartoonName, cartoonType, popularityIndex));
cartoonStars.get(counter).setName(cartoonName);
cartoonStars.get(counter).setType(cartoonType);
cartoonStars.get(counter).setPopularityIndex(popularityIndex);
moreInput = continueInput(stdin);
if (moreInput) {
counter++;
}
} while (moreInput);
}
public static String cartoonName(Scanner stdin) {
String name;
String name1;
int a = 1;
System.out.print("Please enter the name of the cartoon character: ");
name = stdin.nextLine();
do {
name1 = name;
for (int i = 0; i < name.length(); i++) {
if (!Character.isLetter(name.charAt(i))) {
System.out.println("Please ensure you've entered the correct name. Re-enter the name or enter 'continue' to proceed: ");
name = stdin.nextLine();
if (name.equalsIgnoreCase("continue")) {
a = 0;
name = name1;
} else {
a = 1;
}
} else {
a = 0;
}
}
} while (a == 1);
return name;
} // end of cartoonName method
public static CartoonType cartoonType(Scanner stdin) {
int cartoonType = 0;
CartoonType cType = CartoonType.valueOf("NULL");
int a;
do {
try {
System.out.print("Please enter a number corresponding to the type of cartoon character below.\n"
+ "1 = FOX,2 = CHICKEN,3 = RABBIT,4 = MOUSE,5 = DOG,\n6 = CAT,7 = BIRD,8 = FISH,9 = DUCK,10 = RAT\n"
+ "Please enter the type of cartoon character: ");
cartoonType = stdin.nextInt();
while (cartoonType < 1 || cartoonType > 10) {
System.out.print("Sorry, please enter a number from 1 to 10. The corresponding types are:/n"
+ "1 = FOX,2 = CHICKEN,3 = RABBIT,4 = MOUSE,5 = DOG,\n6 = CAT,7 = BIRD,8 = FISH,9 = DUCK,10 = RAT\n");
cartoonType = stdin.nextInt();
}
a = 0;
} catch (InputMismatchException ex) {
System.out.print("Sorry, please enter only integer values.");
a = 1;
stdin.nextLine(); // drop last input
}
} while (a == 1);
switch (cartoonType) {
case 1:
cType = CartoonType.valueOf("FOX");
break;
case 2:
cType = CartoonType.valueOf("CHICKEN");
break;
case 3:
cType = CartoonType.valueOf("RABBIT");
break;
case 4:
cType = CartoonType.valueOf("MOUSE");
break;
case 5:
cType = CartoonType.valueOf("DOG");
break;
case 6:
cType = CartoonType.valueOf("CAT");
break;
case 7:
cType = CartoonType.valueOf("BIRD");
break;
case 8:
cType = CartoonType.valueOf("FISH");
break;
case 9:
cType = CartoonType.valueOf("DUCK");
break;
case 10:
cType = CartoonType.valueOf("RAT");
break;
}
return cType;
} // end of cartoonType method
public static int popularityNumber(Scanner stdin) {
int popNum = 0;
int a;
do {
try {
System.out.print("Please enter a cartoon popularity number from 1 to 10, with 10 being the highest: ");
popNum = stdin.nextInt();
while (popNum < 1 || popNum > 10) {
System.out.print("Sorry, please enter a value from 1 to 10: ");
popNum = stdin.nextInt();
}
a = 1;
} catch (InputMismatchException ex) {
a = 0;
System.out.print("Sorry, please enter only integer values.");
stdin.next();
}
} while (a == 0);
return popNum;
} // end of popularityNumber method
public static boolean continueInput(Scanner stdin) {
boolean moreInput = false;
int a = 1;
System.out.print("More input? Enter 'yes' for more input, or 'no' to quit: ");
String input = stdin.next();
do {
for (int i = 0; i < input.length(); i++) {
if (!Character.isLetter(input.charAt(i))) {
System.out.println("Please enter only 'yes' or 'no'.");
stdin.next();
a = 1;
} else if (input.equalsIgnoreCase("yes")) {
a = 0;
moreInput = true;
} else if (input.equalsIgnoreCase("no")) {
a = 0;
moreInput = false;
} else {
a = 1;
System.out.print("Please enter only 'yes' or 'no'.");
stdin.next();
}
}
} while (a == 1);
return moreInput;
}
}
这是我的另一堂课：
public class CartoonStar {
private String name;
private CartoonType type; //enum types
private int popularityIndex; //1 to 10 10 being the most popular
public CartoonStar() {
}//end no argument construtor
public CartoonStar(String name,CartoonType type, int popularityIndex) {
setName(name);
setType(type);
setPopularityIndex(popularityIndex);
}//end full constructor
//getters and setters
public void setName(String name) {
this.name = name;
}
public String getName() {
return name;
}
public void setType(CartoonType type) {
this.type = type;
}
public CartoonType getType() {
return type;
}
public void setPopularityIndex(int popularityIndex){
this.popularityIndex = popularityIndex;
}
public int getPopularityIndex(){
return popularityIndex;
}
}//end of class CartoonStar
这是我的代码的示例输出：
Please enter the name of the cartoon character: w
Please enter a number corresponding to the type of cartoon character below.
1 = FOX,2 = CHICKEN,3 = RABBIT,4 = MOUSE,5 = DOG,
6 = CAT,7 = BIRD,8 = FISH,9 = DUCK,10 = RAT
Please enter the type of cartoon character: 2
Please enter a cartoon popularity number from 1 to 10, with 10 being the highest: 2
More input? Enter 'yes' for more input, or 'no' to quit: yes
Please enter the name of the cartoon character: w
BUILD STOPPED (total time: 11 seconds)
此时我停止了该计划，因为它并没有让我超越这一点。我的main方法中的循环问题是什么？我没有在没有明确命名的情况下制作对象，所以我对如何创建它们感到困惑，以后能够从我的arraylist中回忆它们。
答案 0 :(得分：0)
无限循环，
您需要将用户输入的新值分配给continueInput
喜欢input = stdin.next();
所以将其改为以下
public static boolean continueInput(Scanner stdin) {
boolean moreInput = false;
int a = 1;
System.out.print("More input? Enter 'yes' for more input, or 'no' to quit: ");
String input = stdin.next();
do {
for (int i = 0; i < input.length(); i++) {
if (!Character.isLetter(input.charAt(i))) {
System.out.println("Please enter only 'yes' or 'no'.");
input = stdin.next();
a = 1;
} else if (input.equalsIgnoreCase("yes")) {
a = 0;
moreInput = true;
} else if (input.equalsIgnoreCase("no")) {
a = 0;
moreInput = false;
} else {
a = 1;
System.out.print("Please enter only 'yes' or 'no'.");
input = stdin.next();
}
}
} while (a == 1);
return moreInput;
}
答案 1 :(得分：0)
以下是已更正的主要课程（卡通星级课程未更改）：
public class Main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
Scanner stdin = new Scanner(System.in);
ArrayList<CartoonStar> cartoonStars = new ArrayList<CartoonStar>();
String cartoonName;
CartoonType cartoonType;
String cartoonTypeString;
int popularityIndex;
boolean moreInput;
int counter = 0;
do {
cartoonName = cartoonName(stdin);
cartoonType = cartoonType(stdin);
cartoonTypeString = cartoonType.toString();
popularityIndex = popularityNumber(stdin);
cartoonStars.add(new CartoonStar(cartoonName, cartoonType, popularityIndex));
cartoonStars.get(counter).setName(cartoonName);
cartoonStars.get(counter).setType(cartoonType);
cartoonStars.get(counter).setPopularityIndex(popularityIndex);
moreInput = continueInput(stdin);
counter++;
} while (moreInput == true);
} // end of main method
public static String cartoonName(Scanner stdin) {
String name;
String name1;
int a = 1;
System.out.print("Please enter the name of the cartoon character: ");
name = stdin.nextLine();
do {
name1 = name;
for (int i = 0; i < name.length(); i++) {
if (!Character.isLetter(name.charAt(i))) {
System.out.println("Please ensure you've entered the correct name. Re-enter the name or enter 'continue' to proceed: ");
name = stdin.nextLine();
if (name.equalsIgnoreCase("continue")) {
a = 0;
name = name1;
} else {
a = 1;
}
} else {
a = 0;
}
}
} while (a == 1);
return name;
} // end of cartoonName method
public static CartoonType cartoonType(Scanner stdin) {
int cartoonType = 0;
CartoonType cType = CartoonType.valueOf("NULL");
int a;
do {
try {
System.out.print("Please enter a number corresponding to the type of cartoon character below.\n"
+ "1 = FOX,2 = CHICKEN,3 = RABBIT,4 = MOUSE,5 = DOG,\n6 = CAT,7 = BIRD,8 = FISH,9 = DUCK,10 = RAT\n"
+ "Please enter the type of cartoon character: ");
cartoonType = stdin.nextInt();
while (cartoonType < 1 || cartoonType > 10) {
System.out.print("Sorry, please enter a number from 1 to 10. The corresponding types are:/n"
+ "1 = FOX,2 = CHICKEN,3 = RABBIT,4 = MOUSE,5 = DOG,\n6 = CAT,7 = BIRD,8 = FISH,9 = DUCK,10 = RAT\n");
cartoonType = stdin.nextInt();
}
a = 0;
} catch (InputMismatchException ex) {
System.out.print("Sorry, please enter only integer values.");
a = 1;
stdin.nextLine(); // drop last input
}
} while (a == 1);
switch (cartoonType) {
case 1:
cType = CartoonType.valueOf("FOX");
break;
case 2:
cType = CartoonType.valueOf("CHICKEN");
break;
case 3:
cType = CartoonType.valueOf("RABBIT");
break;
case 4:
cType = CartoonType.valueOf("MOUSE");
break;
case 5:
cType = CartoonType.valueOf("DOG");
break;
case 6:
cType = CartoonType.valueOf("CAT");
break;
case 7:
cType = CartoonType.valueOf("BIRD");
break;
case 8:
cType = CartoonType.valueOf("FISH");
break;
case 9:
cType = CartoonType.valueOf("DUCK");
break;
case 10:
cType = CartoonType.valueOf("RAT");
break;
}
return cType;
} // end of cartoonType method
public static int popularityNumber(Scanner stdin) {
int popNum = 0;
int a;
do {
try {
System.out.print("Please enter a cartoon popularity number from 1 to 10, with 10 being the highest: ");
popNum = stdin.nextInt();
while (popNum < 1 || popNum > 10) {
System.out.print("Sorry, please enter a value from 1 to 10: ");
popNum = stdin.nextInt();
}
a = 1;
} catch (InputMismatchException ex) {
a = 0;
System.out.print("Sorry, please enter only integer values.");
stdin.next();
}
} while (a == 0);
return popNum;
} // end of popularityNumber method
public static boolean continueInput(Scanner stdin) {
boolean moreInput = false;
int a;
System.out.print("More input? Enter 'yes' for more input, or 'no' to quit: ");
String input;
do {
switch (input = stdin.next().toLowerCase()) {
case "yes":
a = 0;
moreInput = true;
break;
case "no":
a = 0;
moreInput = false;
break;
default:
a = 1;
System.out.print("Please enter only 'yes' or 'no'.");
}
stdin.nextLine();
} while (a == 1);
return moreInput;
} // end of continueInput method
}