按下"更新"按钮,它应该更新,然后显示更新的记录记录的结果(带有选定列的单个更新记录)。但是,页面仅显示表列名称,没有任何记录和一些错误。请帮忙。
<html>
<head>
<strong><font size="6">Sales Log - Main</font><font size="5"><br />
(Transaction Status Update)</font></strong>
</head>
<body bgcolor="#6E6E6E" text="Azure">
<?php
if(isset($_POST['update']))
{
$dbhost = 'localhost';
$dbuser = 'jack';
$dbpass = 'somepassword';
$myDBname = 'sales';
$conn = mysql_connect($dbhost, $dbuser, $dbpass, $myDBname);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
$FileNumber = mysql_real_escape_string($_POST['FileNumber']);
$Status = mysql_real_escape_string($_POST['Status']);
//$sql = "UPDATE saleslog SET Status = '".$Status."' WHERE FileNumber = '".$FileNumber."'"; //this worked fine then code below was introduced
$sql = "UPDATE saleslog
SET Status = '$Status'
WHERE FileNumber = '$FileNumber'" ;
mysql_select_db('realestate');
$retval = mysql_query( $sql, $conn );
if(! $retval )
{
die('Could not update data: ' . mysql_error());
}
echo "Updated data successfully!\n";
mysql_close($conn);
}
else
{
?>
<form method="post" action="<?php $_PHP_SELF ?>">
<table width="400" border="0" cellspacing="1" cellpadding="2">
<tr>
<br />
<br />
<td width="100">File Number</td>
<td><input name="FileNumber" type="text" id="FileNumber"></td>
</tr>
<tr>
<td width="100">Status</td>
<td><input name="Status" type="text" id="Status" value="Closed"></td>
</tr>
<tr>
<td width="100"> </td>
<td> </td>
</tr>
<tr>
<td width="100"> </td>
<td>
<input name="update" type="submit" id="update" value="Update">
<input name="reset" type="reset" onclick="resetForm(''); return false;" />
</td>
</tr>
</table>
</form>
<?php
}
?>
$sql="SELECT FileNumber, Address, Status FROM $tbl_name";
$result=mysql_query($sql);
?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td>
<table width="400" border="1" cellspacing="0" cellpadding="3">
<tr>
<td colspan="4"><strong>List data from mysql </strong> </td>
</tr>
<tr>
<td align="center"><strong>FileNumber</strong></td>
<td align="center"><strong>Address</strong></td>
<td align="center"><strong>Status</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><? echo $rows['FileNumber']; ?></td>
<td><? echo $rows['Address']; ?></td>
<td><? echo $rows['Status']; ?></td>
</tr>
<?php
}
?>
</table>
</td>
</tr>
</table>
<?php
mysql_close();
?>
答案 0 :(得分:3)
代码中的各种错误。
直接转换为'mysqli'。我没有以任何方式改变逻辑。
经测试的代码:PHP 5.3.18。 mysql 5.5 window xp。
添加了表格布局。
无需删除任何行,因为我已将它们转换为注释。只需复制并粘贴。
<!DOCTYPE HTML">
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF8">
<title>
</title>
</head>
<strong><font size="6">Sales Log - Main</font><font size="5"><br />
(Transaction Status Update)</font></strong>
</head>
<body bgcolor="#6E6E6E" text="Azure">
<?php
// always connect to the database...
$mysqlhost = 'localhost';
$mysqluser = 'jack';
$mysqlpass = 'test';
$myDBname = 'sales'; // should this be 'realestate'
// why select a different database then when you connected? was 'sales'
// mysql_select_db('realestate'); /* why? */
$mysqli = new mysqli($mysqlhost, $mysqluser, $mysqlpass, $myDBname);
if(mysqli_connect_errno())
{
die('Could not connect: ' . mysqli_connect_error());
}
// set the database table to use...
$tbl_name = "`saleslog`";
if (isset($_POST['update'])) // we have some record to change...
{
// do not need to escape input as we will use prepared query and bind variables
$FileNumber = $_POST['FileNumber'];
$Status = $_POST['Status'];
//$sql = "UPDATE saleslog SET Status = '".$Status."' WHERE FileNumber = '".$FileNumber."'"; //this worked fine then code below was introduced
$sql = "UPDATE $tbl_name
SET `Status` = ?
WHERE `FileNumber` = ?" ;
$updateQuery = $mysqli->prepare($sql);
if ($updateQuery === false) { // drat
die('updateQuery: '. $mysqli->error);
}
// bind the variables to the query
$updateQuery->bind_param('si', $Status, $FileNumber);
$allOk = $updateQuery->execute();
if (!$allOk) { // drat
die('updateQuery: '. $updateQuery->error);
}
if ($mysqli->affected_rows >= 1) {
echo "Updated data successfully!<br />";
}
else {
echo "FileNumber: $FileNumber was not changed<br />";
}
}
else
{
?>
<form method="post" action="<?php $_PHP_SELF ?>">
<table width="400" border="0" cellspacing="1" cellpadding="2">
<tr><br /><br />
<td width="100">File Number</td><td>
<input name="FileNumber" type="text" id="FileNumber"></td>
</tr>
<tr>
<td width="100">Status</td><td>
<input name="Status" type="text" id="Status" value="Closed"></td>
</tr>
<tr>
<td width="100"> </td><td> </td>
</tr>
<tr>
<td width="100"> </td><td>
<input name="update" type="submit" id="update" value="Update">
<input name="reset" type="reset" onclick="resetForm(''); return false;" /></td>
</tr>
</table>
</form>
<?php
}
// always use 'prepare'
if (!empty($FileNumber)) {
$whereClause = " WHERE `FileNumber` = ?";
}
else {
$whereClause = " ORDER BY `FileNumber`";
}
$sql = "SELECT `FileNumber`, `Address`, `Status`
FROM $tbl_name
$whereClause";
$selectQuery = $mysqli->prepare($sql);
if (!empty($FileNumber)) {
$selectQuery->bind_param('i', $FileNumber);
$originalFileNumber = $FileNumber;
}
$allOk = $selectQuery->execute();
if (!$allOk) { // drat
die('selectQuery: '. $selectQuery->error);
}
// results will be placed in these three variables when we fetch the row later
$selectQuery->bind_result($FileNumber, $Address, $Status);
?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td>
<table width="400" border="1" cellspacing="0" cellpadding="3">
<tr>
<td colspan="4"><strong>List data from mysql </strong> </td>
</tr>
<tr>
<td align="center"><strong>FileNumber</strong></td>
<td align="center"><strong>Address</strong></td>
<td align="center"><strong>Status</strong></td>
</tr>
<?php $rowCount = 0; ?>
<?php while($selectQuery->fetch()): // the data will be in the 'bind_result' variables ?>
<tr>
<td><?= $FileNumber ?></td>
<td><?= $Address; ?></td>
<td><?= $Status; ?></td>
</tr>
<?php $rowCount++; ?>
<?php endwhile; ?>
</table>
</td>
</tr>
<td>
<?php if ($rowCount >= 1): ?>
<strong><?php echo $rowCount; echo $rowCount == 1 ? ' row found' : ' rows found'; ?></strong>
<?php elseif (!empty($originalFileNumber)): ?>
<strong>No rows found for FileNumber: <?php echo $originalFileNumber; ?></strong>
<?php else: ?>
<strong>No rows found in the table!!!></strong>
<?php endif ?>
</td>
</table>
</body>
</html>
<?php
$mysqli->close(); // free the database connection -- not needed but harmless
?>
表格数据:
FileNumber Status Address
---------- ------ ---------------
1 open here at home!
2 Closed what ever
表格布局:
*DDL Information*/
-------------------
CREATE TABLE `saleslog` (
`FileNumber` int(11) NOT NULL,
`Status` varchar(128) COLLATE utf8_unicode_ci NOT NULL DEFAULT '0',
`Address` varchar(512) COLLATE utf8_unicode_ci NOT NULL,
PRIMARY KEY (`FileNumber`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci